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grok-4-fast-reasoning_vs_claude-opus-4-7.jsonl — 10 puzzles

grok-4-fast-reasoning
-3
vs
claude-opus-4-7
-1
#1 Sample Solution Wrong
def mystery(x):
    z = str(x)
    p1 = 111 * 1
    q1 = 98 + 0
    r2 = 102
    s3 = 117 - 0
    t4 = 100 + 15
    u5 = 99
    v6 = 97 * 1
    w7 = 116
    x8 = 101 + 0
    y9 = 100
    temp = p1 + q1 + r2 + s3 + t4 + u5 + v6 + w7 + x8 + y9
    if temp % 1000 == 985:
        target = chr(p1) + chr(q1) + chr(r2) + chr(s3) + chr(t4) + chr(u5) + chr(v6) + chr(w7) + chr(x8) + chr(y9)
        return z == target
    return False
"obfuscated"
Proposer: grok-4-fast-reasoning Solver: claude-opus-4-7
-1 vs 0
#2 Solved
def mystery(x):
    if not isinstance(x, int): return False
    if not (100000 <= x < 1000000): return False
    
    r1 = x - 17 * (x // 17)
    r2 = x - 23 * (x // 23)
    r3 = x - 31 * (x // 31)
    
    if r1 * r2 * r3 != 385: return False
    if r1 + r2 + r3 != 23: return False
    if (r1 ^ r2 ^ r3) != 9: return False
    
    if r1 >= 17 or r2 >= 23 or r3 >= 31: return False
    if r1 == r2 or r2 == r3 or r1 == r3: return False
    
    # Specific mod check disguised
    if (x * x) % 17 != 8: return False  # 5^2=25 mod 17 = 8
    if (x + 12) % 23 != 0: return False  # 11+12=23 ≡ 0
    if (x - 7) % 31 != 0: return False
    
    digits = [int(c) for c in str(x)]
    if sum(digits) != 30: return False
    if len(digits) != 6: return False
    
    return True
642792
642792
Proposer: claude-opus-4-7 Solver: grok-4-fast-reasoning
-1 vs 0
#3 Sample Solution Wrong
def mystery(x):
    z = str(x)
    if len(z) != 6:
        return False
    # Misleading computations
    k1 = 42 * 2 + 31  # irrelevant
    m2 = len(z) * 17   # irrelevant
    if k1 + m2 != 173:  # 84+31=115? Wait, no: 42*2=84 +31=115, but + len*17=102, total 217 !=173, wait fix.
    # Actually make the irrelevant check always true for len=6
    if (42 * 2 + 31) + (len(z) * 17) != 217:
        return False  # This will be true only if len=6, since 84+31=115, 6*17=102, 115+102=217
    # Now real checks, obfuscated per char
    o1 = ord(z[0])
    if (o1 * 23) % 1000 != 645: return False  # 115*23=2645 %1000=645
    p2 = ord(z[1])
    if p2 - (5**3 + 26) != 0: return False  # 101 - (125+26)=101-151? Wait no.
    # Better: for 101: 101 == 100 +1, but obscure: (10**2) +1
    # But to check: compute expected and compare.
    # Let's do direct but with math.
    if not (ord(z[0]) == 5 * 23): return False  #115
    if not (ord(z[1]) == 11 * 9 + 2): return False  #99+2=101
    if not (ord(z[2]) == 9 * 11): return False  #99
    if not (ord(z[3]) == 6 * 19): return False  #114
    if not (ord(z[4]) == 100 + 1): return False  #101
    if not (ord(z[5]) == 4 * 29): return False  #116
    # Red herring sum
    total = sum(ord(c) for c in z)
    if total % 7 != 5: return False  # Check if always true: sum=115+101+99+114+101+116=646, 646/7=92.285, 7*92=644, 646-644=2, !=5? Wait, make it true.
    # Actual 646 %7: 644 is 7*92, 646-644=2, so %7=2. So if total %7 ==2: but to make it seem check.
    # But since it's for this specific, it's fine, but to obscure, perhaps compute something that equals.
    # Actually, to make it part of obfuscation, but since it's specific, any check that's true for it is fine, but to hard, make misleading.
    # For now, add a check that's always true for this sum.
    if total != 646: return False  # But that's direct, bad.
    # Obscure the 646.
    if total != (600 + 46): return False  # Still obvious.
    # Better: if total // 10 != 64 or total %10 !=6: return False  # But solver can see.
    # To make hard, perhaps encode 646 as sum of other things.
    # But let's use: if (total * 3) % 1000 != 938: return False  # 646*3=1938 %1000=938
    yes.
    # Also add type check or something.
    return True
"secret"
Proposer: grok-4-fast-reasoning Solver: claude-opus-4-7
-2 vs 0
#4 Solved
def mystery(x):
    if not isinstance(x, str): return False
    if len(x) != 8: return False
    if not x.isalpha() or not x.islower(): return False
    
    a = [ord(c) - ord('a') for c in x]
    
    if (3*a[0] + 5*a[1]) % 26 != 7: return False
    if (a[1] + 7*a[2]) % 26 != 12: return False
    if (a[2] + a[3]) % 26 != 4: return False
    if (a[3] - a[4]) % 26 != 9: return False
    if (a[4] + a[5]) % 26 != 22: return False
    if (a[5] + 3*a[6]) % 26 != 11: return False
    if (a[6] + a[7]) % 26 != 19: return False
    if (a[0] + a[7]) % 26 != 14: return False
    if sum(a) % 26 != 8: return False
    
    return True
"vukullat"
"ihxhyyng"
Proposer: claude-opus-4-7 Solver: grok-4-fast-reasoning
-2 vs 0
#5 Solved
def mystery(x):
    if not isinstance(x, int): return False
    if not (10000 <= x < 100000): return False
    
    r1 = x % 13
    r2 = x % 17
    r3 = x % 19
    r4 = x % 23
    
    if r1 * r2 * r3 * r4 != 5712: return False
    if r1 + r2 + r3 + r4 != 42: return False
    if r1 ^ r2 ^ r3 ^ r4 != 20: return False
    if r1**2 + r2**2 + r3**2 + r4**2 != 558: return False
    if (r1 + r4) * (r2 + r3) != 425: return False
    
    # Red herring: seems like avoiding multiples of 7, but irrelevant since the target isn't
    if x % 7 == 0: return False
    
    # Another misleading check: looks like a parity or something, but holds for target
    if (r1 + r3) % 5 != 2: return False  # 8+14=22 %5=2, yes
    
    return True
12345
12345
Proposer: grok-4-fast-reasoning Solver: claude-opus-4-7
-2 vs 0
#6 Solved
def mystery(x):
    if not isinstance(x, int): return False
    if not (1000000 <= x < 10000000): return False
    
    if pow(x, 2, 1009) != 592: return False
    if pow(x, 3, 1013) != 85: return False
    if pow(x, 5, 1019) != 437: return False
    
    digits = [int(c) for c in str(x)]
    if sum(digits) != 42: return False
    
    xor_val = 0
    for d in digits:
        xor_val ^= d
    if xor_val != 2: return False
    
    if digits[0] * digits[6] != 27: return False
    if digits[1] - digits[5] != 4: return False
    
    return True
9876543
9876543
Proposer: claude-opus-4-7 Solver: grok-4-fast-reasoning
-2 vs 0
#7 Sample Solution Wrong
def mystery(x):
    if not isinstance(x, str): return False
    z = x
    if len(z) != 7: return False
    if not z.isalpha() or not z.islower(): return False
    
    a = [ord(c) - ord('a') for c in z]
    
    # Red herring computations
    temp1 = len(z) * 11 + 4  # 77 + 4 = 81
    temp2 = 25 * 3 + 2  # 77
    if (temp1 - temp2) % 26 != 4: return False  # 81-77=4, always true
    
    # Intertwined checks
    if (3 * a[0] + a[1]) % 26 != 16: return False
    if (a[1] + 4 * a[2]) % 26 != 20: return False
    if (a[2] + a[3]) % 26 != 13: return False
    if ((2 * a[3] - a[4]) % 26) != 7: return False
    if (a[4] + a[5]) % 26 != 13: return False
    if ((a[5] - a[6]) % 26) != 8: return False
    if (a[6] + a[0]) % 26 != 2: return False
    
    # Non-linear product checks
    if (a[0] * a[6]) % 26 != 10: return False
    if (a[1] * a[5]) % 26 != 10: return False
    if (a[2] * a[3]) % 26 != 0: return False
    if (a[3] * a[4]) % 26 != 13: return False
    
    # Aggregate checks
    s = sum(a)
    if (s * 3) % 100 != 0: return False
    
    xor_val = 0
    for val in a:
        xor_val ^= val
    if xor_val != 2: return False
    
    # Red herring subset sum
    if (a[0] + a[3] + a[6]) % 10 != 1: return False
    
    return True
quantum
Proposer: grok-4-fast-reasoning Solver: claude-opus-4-7
-3 vs 0
#8 Sample Solution Wrong
def mystery(x):
    if not isinstance(x, int): return False
    if not (100000 <= x < 1000000): return False
    
    # Modular residue constraints
    if x % 7 != 4: return False
    if x % 11 != 7: return False
    if x % 13 != 11: return False
    if x % 17 != 15: return False
    if x % 19 != 14: return False
    
    # Quadratic residue check
    if pow(x, 2, 1009) != 173: return False
    
    s = str(x)
    digits = [int(c) for c in s]
    if sum(digits) != 28: return False
    if digits[0] * digits[5] != 16: return False
    if digits[1] - digits[2] != 6: return False
    if digits[3] + digits[4] != 10: return False
    
    # Red herring that's compatible
    xor_val = 0
    for d in digits:
        xor_val ^= d
    if xor_val != 4: return False
    
    return True
271828
Proposer: claude-opus-4-7 Solver: grok-4-fast-reasoning
-3 vs -1
#9 Solved
def mystery(x):
    if not isinstance(x, str): return False
    if len(x) != 6: return False
    if not x.isalpha() or not x.islower(): return False
    
    a = [ord(c) - ord('a') for c in x]
    
    # Red herring
    temp = len(x) * 4 + 2
    if temp % 26 != 0: return False
    
    # Modular checks
    if (a[0] + a[5]) % 26 != 4: return False
    if (a[1] + a[3]) % 26 != 19: return False
    if (a[2] + a[4]) % 26 != 20: return False
    if (a[0] + a[2] + a[4]) % 26 != 24: return False
    if (a[1] * a[4]) % 26 != 0: return False
    if (3 * a[0] + a[1] - a[3]) % 26 != 19: return False
    if (a[2] * a[4] + a[5]) % 26 != 18: return False
    if (a[0] * a[3] + a[5]) % 26 != 24: return False
    if (a[1] - a[2]) % 26 != 5: return False
    
    # Aggregate checks
    s = sum(a)
    if (s * 2) % 100 != 86: return False
    
    xor_val = a[0]
    for i in range(1, 6):
        xor_val ^= a[i]
    if xor_val != 11: return False
    
    return True
"enigma"
"enigma"
Proposer: grok-4-fast-reasoning Solver: claude-opus-4-7
-3 vs -1
#10 Solved
def mystery(x):
    if not isinstance(x, int): return False
    if not (1000000 <= x < 10000000): return False
    
    # Modular residue constraints (CRT)
    if x % 7 != 5: return False
    if x % 11 != 2: return False
    if x % 13 != 12: return False
    if x % 17 != 16: return False
    if x % 19 != 7: return False
    
    # Quadratic residue mod 1009
    if pow(x, 2, 1009) != 302: return False
    
    # Digit constraints
    s = str(x)
    digits = [int(c) for c in s]
    if sum(digits) != 37: return False
    if digits[0] + digits[6] != 11: return False
    if digits[2] * digits[4] != 2: return False
    
    # Bit popcount
    if bin(x).count('1') != 10: return False
    
    # XOR of digits
    xor_val = 0
    for d in digits:
        xor_val ^= d
    if xor_val != 7: return False
    
    return True
4826197
4826197
Proposer: claude-opus-4-7 Solver: grok-4-fast-reasoning
-3 vs -1