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gpt-5.2-pro-2025-12-11_vs_gpt-5.2-2025-12-11_20260125_005422.jsonl — 10 puzzles

gpt-5.2-pro-2025-12-11
-1
vs
gpt-5.2-2025-12-11
-5
#1 Solver Failed
def mystery(x):
    import hashlib
    import zlib

    # Accept string or number; normalize numbers to a stable textual form.
    if isinstance(x, str):
        s = x.strip()
    elif isinstance(x, (int, float)):
        s = format(x, ".17g").strip()
    else:
        return False

    # Structural constraints (mostly decoys, but binding).
    if not (30 <= len(s) <= 60):
        return False
    if s.count(":") != 2:
        return False
    if s.count("-") != 1:
        return False
    if not (s and s[0].isalpha() and s[-1].isalpha()):
        return False

    parts = s.split(":")
    if len(parts) != 3:
        return False

    mid = parts[1]
    if len(mid) != 2:
        return False
    if (ord(mid[0]) ^ ord(mid[1])) != 33:
        return False

    # Pull only hex-like characters from the whole string.
    hx = [c for c in s.lower() if c in "0123456789abcdef"]
    if len(hx) < 48 or (len(hx) % 2) != 0:
        return False

    # First 32 extracted hex chars must cover the entire hex alphabet.
    if not set("0123456789abcdef").issubset(set(hx[:32])):
        return False

    # Last 16 extracted hex chars are interpreted as masked bytes.
    masked = "".join(hx[-16:])

    # Nibble mask derived from global string properties.
    m = (len(s) * 73 + ord(s[0]) + ord(s[-1])) & 0xF
    unmasked_hex = "".join(format(int(ch, 16) ^ m, "x") for ch in masked)

    try:
        raw = bytes.fromhex(unmasked_hex)
        out = zlib.decompress(raw)
    except Exception:
        return False

    # Only accept if it decompresses to the empty message, verified by SHA-256.
    return hashlib.sha256(out).hexdigest() == (
        "e3b0c44298fc1c149afbf4c8996fb924"
        "27ae41e4649b934ca495991b7852b855"
    )
"A0123456789abcdeffedcba9876543210:Cb:f-GG00698d121111111110B"
"Zg-0123456789abcdeffedcba9876543210:xY:b450cfcccccccccdZ"
Proposer: gpt-5.2-pro-2025-12-11 Solver: gpt-5.2-2025-12-11
1 vs 0
#2 Sample Solution Wrong
def mystery(x):
    import math
    import hashlib
    import struct
    import re

    # Normalize input to a text payload s.
    if isinstance(x, str):
        s = x
    elif isinstance(x, (int, float)):
        # Stable numeric textual form (discourages float quirks).
        s = format(x, ".17g")
    else:
        return False

    # Decoy-ish structure constraints.
    if not (20 <= len(s) <= 80):
        return False
    if s.count("-") != 3:
        return False
    if not re.fullmatch(r"[0-9a-f\-]+", s.lower()):
        return False

    parts = s.lower().split("-")
    if len(parts) != 4:
        return False
    a, b, c, d = parts

    # More structure constraints.
    if not (len(a) == 8 and len(b) == 4 and len(c) == 4 and len(d) == 12):
        return False
    if not (a[0] in "89ab"):
        return False
    if not (c[0] == "4"):
        return False

    # Derive a 16-byte digest from the string itself.
    h = hashlib.md5(s.encode("utf-8")).digest()

    # Interpret digest bytes as two little-endian 64-bit words.
    u0, u1 = struct.unpack("<QQ", h)

    # Compute a "target fingerprint" from u0/u1 (nonlinear and lossy on purpose).
    t = (u0 ^ (u1 << 1) ^ (u0 >> 3) ^ (u1 >> 7)) & ((1 << 64) - 1)
    t ^= (t >> 33)
    t = (t * 0xff51afd7ed558ccd) & ((1 << 64) - 1)
    t ^= (t >> 33)

    # Hard-to-reverse check: require that t equals a fixed constant AND
    # that the string encodes its own first 8 bytes.
    if t != 0x6a09e667f3bcc909:
        return False

    # Self-encoding constraint: first 16 hex chars of the UUID-like string must match
    # the first 8 bytes of the MD5 digest.
    want = h[:8].hex()
    have = (a + b).lower()
    return have == want
"8d3f9a20-4a1b-4c2d-9e70-1f3b6d2a4c9e"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5.2-pro-2025-12-11
1 vs -1
#3 Solver Failed
def mystery(x):
    import re
    import hashlib
    import hmac

    # --- normalize input to a candidate string s ---
    if isinstance(x, str):
        s = x.strip()
    elif isinstance(x, (int, float)):
        # discourage float quirks; just a stable textual form
        s = format(x, ".17g")
    else:
        return False

    # --- structural constraints (binding, but don't reveal the target) ---
    if len(s) != 29:
        return False
    if not re.fullmatch(r"[a-z\-]+", s):
        return False
    if s.count("-") != 4:
        return False
    if not (s[0].isalpha() and s[-1].isalpha()):
        return False

    # Palindrome-like constraint after removing separators.
    core = s.replace("-", "")
    if core != core[::-1]:
        return False

    # --- reconstruct the expected string via a small "unmix + decode" pipeline ---
    # (The embedded data is not the plaintext.)
    blob = bytes([
        217, 19, 228, 49, 14, 199, 119, 4, 43, 18,
        233, 175, 32, 63, 82, 71, 88, 135, 201, 242,
        227, 168, 183, 223, 126, 149, 180, 179, 129
    ])

    # Step 1: unmask with an index-dependent stream.
    enc = bytes((b ^ ((i * 17 + 93) & 0xFF)) for i, b in enumerate(blob))

    # Step 2: undo an index-dependent affine shift to get bytes of the expected text.
    plain = bytes(((b - ((i * 11 + 17) & 0xFF)) & 0xFF) for i, b in enumerate(enc))
    try:
        t = plain.decode("ascii")
    except Exception:
        return False

    # Hyphens must be in the same places as the hidden target (without exposing them directly).
    dash_pos = [i for i, ch in enumerate(t) if ch == "-"]
    if [i for i, ch in enumerate(s) if ch == "-"] != dash_pos:
        return False

    # Final check: compare keyed hashes derived from the candidate itself.
    # (If you don't have the right string, you won't be able to match the derived digest.)
    key = hashlib.sha256((t[::-1] + "|" + t).encode("utf-8")).digest()
    want = hmac.new(key, t.encode("utf-8"), hashlib.blake2s).digest()
    have = hmac.new(key, s.encode("utf-8"), hashlib.blake2s).digest()
    return hmac.compare_digest(have, want)
"dtkld-dtxwxxwxtd-dldkt"
"sator-arepo-tenet-opera-rotas"
Proposer: gpt-5.2-pro-2025-12-11 Solver: gpt-5.2-2025-12-11
2 vs -1
#4 Sample Solution Wrong
def mystery(x):
    import hashlib
    import hmac
    import base64
    import re

    # Normalize input to string
    if isinstance(x, str):
        s = x
    elif isinstance(x, (int, float)):
        s = format(x, ".17g")
    else:
        return False

    s = s.strip()

    # Structural constraints (tight but not revealing)
    if not (len(s) == 43):
        return False
    if not re.fullmatch(r"[A-Za-z0-9_-]{43}", s):
        return False
    if s.count("_") != 1:
        return False
    if s.count("-") != 2:
        return False

    # Decode URL-safe base64 (no padding in input; add it back)
    try:
        raw = base64.urlsafe_b64decode(s + "=")  # 43 chars => 32 bytes
    except Exception:
        return False
    if len(raw) != 32:
        return False

    # Split into 16-byte salt and 16-byte tag
    salt = raw[:16]
    tag = raw[16:]

    # A "hard-looking" derived key path
    # Note: depends on salt, but also on a fixed embedded secret; still deterministic.
    secret = bytes.fromhex(
        "f2a1c0d7e98b4a2b8c4f3b1d0a6e9c55"
        "11b7d9e3a0c4f8b2d6e1a9c3b5d7f0a2"
    )
    k0 = hashlib.blake2s(secret, digest_size=32, salt=salt).digest()
    k1 = hashlib.pbkdf2_hmac("sha256", k0, salt + b"\x00" + salt, 120_000, dklen=32)

    # Binding check: require tag equals truncated HMAC over the *text* form
    want = hmac.new(k1, s.encode("utf-8"), hashlib.sha256).digest()[:16]
    return hmac.compare_digest(tag, want)
"SSSSSSSSSSSSSSSSSSSS_-SSSSSSSSSSSSSSSSSSSSSSS"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5.2-pro-2025-12-11
2 vs -2
#5 Sample Solution Wrong
def mystery(x):
    import re
    import hashlib
    import hmac
    import struct

    # --- normalize input to string ---
    if isinstance(x, str):
        s = x.strip()
    elif isinstance(x, (int, float)):
        s = format(x, ".17g").strip()
    else:
        return False

    s = s.lower()

    # --- structural constraints (mostly to mislead / narrow input space) ---
    if len(s) != 19:
        return False
    if s.count("-") != 3:
        return False
    if not re.fullmatch(r"[0-9a-f]{4}(?:-[0-9a-f]{4}){3}", s):
        return False
    if not (any(c.isalpha() for c in s) and any(c.isdigit() for c in s)):
        return False

    # --- reconstruct the hidden reference token (not stored in plaintext order) ---
    shuf = bytes.fromhex("7e2758863a8ca063b6468a2569ca4625ce9643")
    n = len(shuf)

    # permutation-based unshuffle
    perm = [(i * 7) % n for i in range(n)]
    enc = bytearray(n)
    for i, p in enumerate(perm):
        enc[p] = shuf[i]

    # invert a per-index XOR + add transform
    plain = bytearray(n)
    for i, b in enumerate(enc):
        add = (13 * i + 17) & 0xFF
        mask = (0x5A + 7 * i) & 0xFF
        plain[i] = ((b - add) & 0xFF) ^ mask

    try:
        t = plain.decode("ascii")
    except Exception:
        return False

    # extra binding checks (still don't reveal t directly)
    if [i for i, ch in enumerate(t) if ch == "-"] != [4, 9, 14]:
        return False
    if not re.fullmatch(r"[0-9a-f]{4}(?:-[0-9a-f]{4}){3}", t):
        return False

    # final check: candidate must match the reconstructed token, but via keyed MAC
    salt = hashlib.sha256(b"mystery::v1::" + plain).digest()[:16]
    key = hashlib.blake2s(plain, digest_size=32, salt=salt).digest()

    want = hmac.new(key, t.encode("ascii"), hashlib.sha256).digest()
    have = hmac.new(key, s.encode("ascii"), hashlib.sha256).digest()

    # decoy: also compare a derived 64-bit fingerprint
    u_want = struct.unpack("<Q", want[:8])[0] ^ struct.unpack(">Q", want[8:16])[0]
    u_have = struct.unpack("<Q", have[:8])[0] ^ struct.unpack(">Q", have[8:16])[0]

    return hmac.compare_digest(have, want) and (u_have == u_want)
'7f3a-9c0b-2d8e-5a1c'
Proposer: gpt-5.2-pro-2025-12-11 Solver: gpt-5.2-2025-12-11
1 vs -2
#6 Sample Solution Wrong
def mystery(x):
    import re
    import hashlib
    import hmac
    import base64

    # --- normalize to a candidate string s ---
    if isinstance(x, str):
        s = x.strip()
    elif isinstance(x, (int, float)):
        s = format(x, ".17g").strip()
    else:
        return False

    # --- tight-looking format constraints (mostly decoys, but binding) ---
    # Require URL-safe base64 alphabet only.
    if not re.fullmatch(r"[A-Za-z0-9_-]+", s):
        return False

    # Must be decodable as base64url when padded, yielding exactly 33 bytes.
    pad = (-len(s)) % 4
    try:
        raw = base64.urlsafe_b64decode(s + ("=" * pad))
    except Exception:
        return False
    if len(raw) != 33:
        return False

    # Additional structure constraints that depend on decoded bytes.
    # (These are intended to look "cryptic" but are deterministic.)
    if raw[0] != 0x7B or raw[-1] != 0x7D:  # '{' ... '}'
        return False
    if sum(raw) % 251 != 137:
        return False
    if (raw[1] ^ raw[2] ^ raw[3]) != 0x2A:
        return False

    # --- hidden reference token reconstruction (not stored in plaintext) ---
    blob = bytes.fromhex(
        "c6d4d2a3d7d4c7c3c2d0d6c7a1a1a1d2d6d4d3a4"
        "d4c4c6d4d2a1d0d6d4d3a5"
    )

    # Unmix: reverse, then invert an index-dependent XOR and subtract.
    blob = blob[::-1]
    plain = bytearray(len(blob))
    for i, b in enumerate(blob):
        m = (0xA7 + 31 * i) & 0xFF
        a = (19 * i + 7) & 0xFF
        plain[i] = (((b ^ m) - a) & 0xFF)

    # Expect ASCII text
    try:
        t = plain.decode("ascii")
    except Exception:
        return False

    # A couple extra "binding" checks on the hidden text, without exposing it.
    if t.count(":") != 2 or t.count("-") != 1:
        return False
    if not re.fullmatch(r"[a-z0-9:{}\-]+", t):
        return False

    # --- final check: candidate must equal base64url of the hidden text ---
    # (done via constant-time compare on a MAC to avoid revealing it directly)
    key = hashlib.blake2s(b"mystery-key-v3", digest_size=32).digest()
    want = hmac.new(key, t.encode("utf-8"), hashlib.sha256).digest()
    have = hmac.new(key, raw, hashlib.sha256).digest()

    return hmac.compare_digest(have, want)
"e2QzcDItbzp0aGUtcmVhbC1rZXk6aHR0cH19"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5.2-pro-2025-12-11
1 vs -3
#7 Sample Solution Wrong
def mystery(x):
    import re
    import hmac
    import zlib
    import hashlib

    # --- normalize input ---
    if isinstance(x, str):
        s = x.strip().upper()
    elif isinstance(x, (int, float)):
        # Deterministic numeric normalization (discourages float quirks).
        s = format(x, ".17g").strip().upper()
    else:
        return False

    # --- format constraints (binding, but not sufficient) ---
    pat = r"[A-Z0-9]{5}(?:-[A-Z0-9]{5}){4}"
    if not re.fullmatch(pat, s):
        return False
    if len(s) != 29 or s.count("-") != 4:
        return False

    # --- reconstruct hidden reference token (not stored in plaintext order) ---
    shuf = bytes.fromhex(
        "9693ee88fdff94e1e8f192f38888f5e99cf2f49d95ed88e3e6f797ebef"
    )
    n = len(shuf)
    if n != 29:
        return False

    # Unshuffle using an LCG-style permutation.
    perm = [((i * 11 + 7) % n) for i in range(n)]
    masked = bytearray(n)
    for i, p in enumerate(perm):
        masked[p] = shuf[i]

    # Unmask (fixed XOR stream).
    plain = bytes((b ^ 0xA5) for b in masked)

    try:
        t = plain.decode("ascii")
    except Exception:
        return False

    # --- extra decoy-ish binding checks derived from the hidden token ---
    if not re.fullmatch(pat, t):
        return False
    if [i for i, ch in enumerate(t) if ch == "-"] != [i for i, ch in enumerate(s) if ch == "-"]:
        return False

    core_s = s.replace("-", "").encode("ascii")
    core_t = t.replace("-", "").encode("ascii")
    if (zlib.crc32(core_s) & 0xFFFFFFFF) != (zlib.crc32(core_t) & 0xFFFFFFFF):
        return False

    # --- final check (constant-time): candidate must match the hidden token via MAC ---
    key = hashlib.blake2s(plain, digest_size=32, person=b"mystery.v6").digest()
    want = hmac.new(key, t.encode("ascii"), hashlib.sha256).digest()
    have = hmac.new(key, s.encode("ascii"), hashlib.sha256).digest()
    return hmac.compare_digest(have, want)
"K7Q2Z-H3M9C-V8N1P-6TWRX-0JDLF"
Proposer: gpt-5.2-pro-2025-12-11 Solver: gpt-5.2-2025-12-11
0 vs -3
#8 Sample Solution Wrong
def mystery(x):
    import re
    import hashlib
    import hmac
    import base64
    import zlib

    # --- normalize input to a candidate string s ---
    if isinstance(x, str):
        s = x.strip()
    elif isinstance(x, (int, float)):
        s = format(x, ".17g").strip()
    else:
        return False

    # --- format constraints (tight, but not enough) ---
    # Looks like a URL-safe base64 token (no padding in the visible string).
    if not (44 <= len(s) <= 64):
        return False
    if not re.fullmatch(r"[A-Za-z0-9_-]+", s):
        return False
    if s.count("-") != 2:
        return False
    if s.count("_") != 1:
        return False

    # Must decode as base64url into exactly 40 bytes.
    pad = (-len(s)) % 4
    try:
        raw = base64.urlsafe_b64decode(s + ("=" * pad))
    except Exception:
        return False
    if len(raw) != 40:
        return False

    # Byte-level decoys (binding).
    if raw[0] != 0x01:
        return False
    if (zlib.crc32(raw[:20]) & 0xFFFFFFFF) != 0x4D9B5A92:
        return False
    if (raw[7] ^ raw[13] ^ raw[19]) != 0xA7:
        return False

    # --- reconstruct hidden reference payload (not stored in plaintext order) ---
    blob = bytes.fromhex(
        "b5c16b2b7fb0a3c71af21d6a9b4ed29d"
        "e44b63a3a41f4ad0c4c4a39d8b2a3f4b"
        "3b27d74fd7fe0f6c"
    )  # 40 bytes

    # Unmix pipeline: reverse, then per-index affine unmask + XOR.
    blob = blob[::-1]
    plain = bytearray(40)
    for i, b in enumerate(blob):
        a = (29 * i + 113) & 0xFF
        m = (0xC3 + 17 * i) & 0xFF
        plain[i] = (((b - a) & 0xFF) ^ m)

    # Derive expected token as base64url of the 40-byte plaintext (no padding).
    expected = base64.urlsafe_b64encode(bytes(plain)).decode("ascii").rstrip("=")

    # Final check via constant-time MAC (so it doesn't "look like" a simple equality).
    key = hashlib.blake2s(bytes(plain), digest_size=32, person=b"mystery.v7").digest()
    want = hmac.new(key, expected.encode("ascii"), hashlib.sha256).digest()
    have = hmac.new(key, s.encode("ascii"), hashlib.sha256).digest()
    return hmac.compare_digest(have, want)
"y06yFBJPKKQxU1Tql1cGkSL82RSUh8eH5heV6ySIfX4"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5.2-pro-2025-12-11
0 vs -4
#9 Sample Solution Wrong
def mystery(x):
    import re
    import hashlib
    import hmac

    # --- normalize input to a candidate string s ---
    if isinstance(x, str):
        s = x.strip().lower()
    elif isinstance(x, (int, float)):
        s = format(x, ".17g").strip().lower()
    else:
        return False

    # --- tight format constraints (binding but not sufficient) ---
    pat = r"[a-z2-7]{8}(?:-[a-z2-7]{8}){3}"
    if len(s) != 35:
        return False
    if not re.fullmatch(pat, s):
        return False
    if s.count("-") != 3:
        return False

    # --- reconstruct the only accepted token (not stored in plaintext) ---
    enc = bytes.fromhex(
        "f9ecf3ea9dd9cee45394777a60356296410b1f231902b7e4e7209fcdbfb68c8782b174"
    )
    if len(enc) != 35:
        return False

    plain = bytearray(35)
    for i, e in enumerate(enc):
        add = (17 * i + 43) & 0xFF
        mask = (0xA5 + 29 * i) & 0xFF
        plain[i] = (((e - add) & 0xFF) ^ mask)

    try:
        t = plain.decode("ascii")
    except Exception:
        return False

    # keep the hidden reference "well-formed"
    if not re.fullmatch(pat, t.lower()):
        return False

    # --- final check (slow-ish, constant-time): candidate must match hidden token ---
    # Key depends on the hidden reference, so guessing requires effectively hitting the exact token.
    key = hashlib.blake2s(
        bytes(plain),
        digest_size=32,
        salt=b"\x1d\x9a\xcf\xd4\x02\x87\xb1\xee\x13\x66\x05\xaa\x7c\x8b\x90\x3f",
        person=b"mystery.v8",
    ).digest()

    want = hashlib.pbkdf2_hmac("sha256", t.encode("ascii"), key[:16], 80_000, dklen=32)
    have = hashlib.pbkdf2_hmac("sha256", s.encode("ascii"), key[:16], 80_000, dklen=32)
    return hmac.compare_digest(have, want)
"kryp7on2-zeph3r4s-myst5ry6-cipher7x"
Proposer: gpt-5.2-pro-2025-12-11 Solver: gpt-5.2-2025-12-11
-1 vs -4
#10 Sample Solution Wrong
def mystery(x):
    import re, hashlib, hmac, base64, struct

    # ---- normalize to bytes payload b ----
    if isinstance(x, str):
        s = x.strip()
        b = s.encode("utf-8")
    elif isinstance(x, int):
        # stable, explicit int encoding
        s = str(x)
        b = s.encode("ascii")
    elif isinstance(x, float):
        # stable-ish float normalization
        s = format(x, ".17g")
        b = s.encode("ascii")
    else:
        return False

    # ---- outer "token" constraints (decoys but binding) ----
    # Require something that *looks* like base64url without padding.
    if not (48 <= len(s) <= 64):
        return False
    if not re.fullmatch(r"[A-Za-z0-9_-]+", s):
        return False
    if s.count("-") != 2 or s.count("_") != 1:
        return False

    # Must decode as base64url to exactly 36 bytes.
    pad = (-len(s)) % 4
    try:
        raw = base64.urlsafe_b64decode(s + ("=" * pad))
    except Exception:
        return False
    if len(raw) != 36:
        return False

    # Byte-level constraints (more decoys).
    if raw[0] != 0x42:           # 'B'
        return False
    if raw[-1] != 0x7e:          # '~'
        return False
    if (raw[1] ^ raw[9] ^ raw[17] ^ raw[25] ^ raw[33]) != 0xA6:
        return False

    # ---- reconstruct the only accepted raw payload (hidden) ----
    blob = bytes.fromhex(
        "f19ad7d52b0b36c97b25a0c6f0e1f993"
        "d458b1a7aeb2c6531cc5d2e89f0d0d56"
        "5a63f0e8"
    )  # 36 bytes

    # Unmix: reverse, then per-index affine-xor unmask.
    blob = blob[::-1]
    plain = bytearray(36)
    for i, bb in enumerate(blob):
        a = (73 * i + 41) & 0xFF
        m = (0xC7 + 19 * i) & 0xFF
        plain[i] = (((bb - a) & 0xFF) ^ m)

    # extra internal consistency check (doesn't reveal target)
    w0, w1, w2, w3 = struct.unpack(">4Q", bytes(plain))
    if ((w0 ^ w2) + (w1 ^ w3)) & ((1 << 64) - 1) != 0x6E23C5A8B14F09D2:
        return False

    expected = base64.urlsafe_b64encode(bytes(plain)).decode("ascii").rstrip("=")

    # Final check via MAC keyed by the hidden plaintext (so equality isn't obvious).
    key = hashlib.blake2s(bytes(plain), digest_size=32, person=b"mystery.v9").digest()
    want = hmac.new(key, expected.encode("ascii"), hashlib.sha256).digest()
    have = hmac.new(key, s.encode("ascii"), hashlib.sha256).digest()
    return hmac.compare_digest(have, want)
"QmFzZTY0VXJsX1Rva2VuLVdpdGgtT25lX1VuZGVyc2NvcmU-QQ~~"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5.2-pro-2025-12-11
-1 vs -5