def mystery(x):
import hashlib, unicodedata, itertools, math
# Accept strings or numbers; normalize to a stable UTF-8 byte sequence.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
b = s.encode('utf-8')
# A few harmless obfuscations to make quick reading slightly harder.
# (They do not change the deterministic result.)
# fold: split into chunks and recombine (no-op for our purposes)
chunks = [b[i:i+7] for i in range(0, len(b), 7)]
folded = b"".join(chunks)
# compute sha256 of the normalized bytes
h = hashlib.sha256(folded).hexdigest()
# the target hash (hidden "secret" preimage). Extremely unlikely to be reversible.
target = "2cf24dba5fb0a30e26e83b2ac5b9e29e" \
"1b161e5c1fa7425e73043362938b9824"
return h == target
def mystery(x):
import hashlib, unicodedata, itertools, math
# Accept strings or numbers; normalize to a stable UTF-8 byte sequence.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKD', s).strip()
b = s.encode('utf-8')
# A few harmless obfuscations to make quick reading slightly harder.
# (They do not change the deterministic result.)
# fold: split into chunks and recombine (no-op for our purposes)
chunks = [b[i:i+8] for i in range(0, len(b), 8)]
folded = b"".join(chunks)
# compute md5 of the normalized bytes
h = hashlib.md5(folded).hexdigest()
# the target hash (hidden "secret" preimage). Extremely unlikely to be reversible.
target = "7d793037a0760186574b0282f2f435e7"
return h == target
def mystery(x):
import hashlib, unicodedata, itertools, math
# Accept strings or numbers; normalize to a stable UTF-8 byte sequence.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
b = s.encode('utf-8')
# A few harmless obfuscations
# interleave: create a slightly transformed view (no effective change to the digest)
interleaved = b''.join(b[i:i+1] for i in range(len(b)))
# compute two different digests
md5_hex = hashlib.md5(interleaved).hexdigest()
sha1_hex = hashlib.sha1(interleaved).hexdigest()
# Two known targets (chosen so that both must match)
target_md5 = "5f4dcc3b5aa765d61d8327deb882cf99"
target_sha1 = "5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8"
return md5_hex == target_md5 and sha1_hex == target_sha1
def mystery(x):
import hashlib, unicodedata, itertools, math
# Accept strings or numbers; normalize to a stable UTF-8 byte sequence.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKD', s).strip()
b = s.encode('utf-8')
# A few harmless obfuscations to make quick reading slightly harder.
# (They do not change the deterministic result.)
# Use itertools to create a chained byte sequence (no-op)
chained = b''.join(itertools.chain.from_iterable([bytes([byte]) for byte in b]))
# compute three different digests
md5_hex = hashlib.md5(chained).hexdigest()
sha1_hex = hashlib.sha1(chained).hexdigest()
sha256_hex = hashlib.sha256(chained).hexdigest()
# Three known targets (chosen so that all must match)
target_md5 = "ed076287532e86365e841e92bfc50d8c"
target_sha1 = "2aae6c35c94fcfb415dbe95f408b9ce91ee846ed"
target_sha256 = "936a185caaa266bb9cbe981e9e05cb78cd732b0b3280eb944412bb6f8f8f07af"
return md5_hex == target_md5 and sha1_hex == target_sha1 and sha256_hex == target_sha256
def mystery(x):
import unicodedata, math, itertools
# Accept strings or numbers; normalize to a stable UTF-8 string.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
# Build a 20-character target by deriving letters from Fibonacci numbers modulo 26.
# The construction below is intentionally written in a slightly indirect style.
a, b = 1, 1
chars = []
for i in range(1, 21):
if i <= 2:
v = 1
else:
# advance the Fibonacci pair; keep full integers (not reduced) then mod 26 when mapping to letters
a, b = b, a + b
v = b
# map to lowercase ASCII letters a..z via (fib mod 26) -> 0..25 then +97
ch = chr((v % 26) + 97)
chars.append(ch)
target = "".join(chars)
# Final conditions: exact equality to the derived target and length sanity check
return s == target and len(s) == 20
def mystery(x):
import unicodedata, math, itertools
# Accept strings or numbers; normalize to a stable UTF-8 string.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
# Helper function to determine if a number is prime, with some indirect conditions.
def is_prime(n):
if n <= 1:
return False
if n == 2 or n == 3:
return True
if n % 2 == 0 or n % 3 == 0:
return False
# Use math to set loop limit indirectly
limit = int(math.sqrt(n)) + 1
for i in range(5, limit, 6):
if n % i == 0 or n % (i + 2) == 0:
return False
return True
# Generate the first 15 primes using itertools.count and filter.
count = itertools.count(2)
primes = []
while len(primes) < 15:
candidate = next(count)
if is_prime(candidate):
primes.append(candidate)
# Map each prime to a character: (prime % 26) + 97
# Introduce a no-op using math for obfuscation
chars = []
for p in primes:
mod = p % 26
adjusted = int(math.floor(mod + 97 - (mod * 0)))
chars.append(chr(adjusted))
target = "".join(chars)
# Final condition: equality and length check
return s == target and len(s) == len(primes)
def mystery(x):
import unicodedata, math
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
# Build a target string of length 24 by taking n! mod 36 for n=1..24,
# mapping 0..9 -> '0'..'9' and 10..35 -> 'a'..'z' (base36 characters).
def to_base36_char(v):
if 0 <= v <= 9:
return chr(ord('0') + v)
if 10 <= v <= 35:
return chr(ord('a') + (v - 10))
# out-of-range (shouldn't happen here)
return '?'
n = 24
f = 1
chars = []
for i in range(1, n + 1):
f = (f * i) % 36
chars.append(to_base36_char(f))
target = "".join(chars)
return s == target and len(s) == n
def mystery(x):
import unicodedata, math, itertools
# Accept strings or numbers; normalize to a stable UTF-8 string.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKD', s).strip()
# LCG parameters with some indirect computation for obfuscation.
m = 997
a = 123
c = int(math.pow(3, 5) * 1.875) # computes to 456 (243 * 1.875 = 456)
initial_seed = 789
# Helper function for LCG update, with no-op math for indirection.
def update(seed):
multiplied = a * seed
added = multiplied + c
modded = added % m
return int(math.floor(modded + 0.0)) # no-op
# Generate 20 characters using LCG.
seed = initial_seed
chars = []
for _ in itertools.repeat(None, 20): # Use itertools for loop indirection
seed = update(seed)
val = seed % 26
ch = chr(val + 97)
chars.append(ch)
target = "".join(chars)
# Final condition: equality and length check
return s == target and len(s) == 20
def mystery(x):
import unicodedata, math, itertools
# Accept strings or numbers; normalize to a stable UTF-8 string.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
# Build a 26-character target in an indirect way.
# We'll generate the first 26 primes, then map each to a base36-like character.
def is_prime(n):
if n < 2:
return False
if n in (2, 3):
return True
if n % 2 == 0:
return False
r = int(math.sqrt(n))
for i in range(3, r + 1, 2):
if n % i == 0:
return False
return True
primes = []
cand = 2
while len(primes) < 26:
if is_prime(cand):
primes.append(cand)
cand += 1
def to_base36_char(v):
# map 0..9 -> '0'..'9', 10..35 -> 'a'..'z'
if 0 <= v <= 9:
return chr(ord('0') + v)
if 10 <= v <= 35:
return chr(ord('a') + (v - 10))
return '?'
chars = []
# The arithmetic below is intentionally simple but written with some indirection
# to make quick eyeballing less straightforward.
for idx, p in enumerate(primes, start=1):
i = int(idx)
# v = (p*(i+3) + i*i + 5) % 36
part1 = p * (i + 3)
part2 = i * i
summed = int(math.floor(part1 + part2 + 5))
v = summed % 36
chars.append(to_base36_char(v))
target = "".join(chars)
# Final condition: exact match and correct length
return s == target and len(s) == len(chars)
def mystery(x):
import unicodedata, math, itertools
# Accept strings or numbers; normalize to a stable UTF-8 string.
try:
s = str(x)
except Exception:
return False
s = unicodedata.normalize('NFKC', s).strip()
# LCG parameters with some indirect computation for obfuscation.
m = 2 ** 10
a = int(math.sqrt(10201))
c = 3**5 + 90
initial_seed = 10**3 // 2
# Helper function for LCG update, with no-op math for indirection.
def update(seed):
multiplied = a * seed
added = multiplied + c
modded = added % m
return int(math.floor(modded + 0.0)) # no-op
# Generate 18 characters using LCG.
seed = initial_seed
chars = []
for _ in itertools.repeat(None, 18): # Use itertools for loop indirection
seed = update(seed)
val = seed % 26
ch = chr(val + 97)
chars.append(ch)
target = "".join(chars)
# Final condition: equality and length check
return s == target and len(s) == 18