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gpt-5-mini-2025-08-07_vs_gpt-5.2-2025-12-11_20260124_044942.jsonl — 10 puzzles

gpt-5-mini-2025-08-07
4
vs
gpt-5.2-2025-12-11
-5
#1 Solver Failed
def mystery(x):
    """
    mystery accepts either an int or a string.
    - If given an int, it returns True iff several intertwined numeric conditions hold.
    - If given a string, it will attempt to interpret the string in base 36 and
      treat that integer the same way (strings that are not valid base-36 fail).
    """
    # Accept base-36 strings by converting them to int and reusing the int branch.
    if isinstance(x, str):
        try:
            return mystery(int(x, 36))
        except Exception:
            return False

    if not isinstance(x, int):
        return False

    # A set of bitwise and arithmetic checks; all must hold for the function to return True.
    # These are intentionally interdependent and non-obvious.
    target_xor_result = ((1 << 31) - 1) * 3               # 3 * (2**31 - 1)
    cond1 = (x ^ 0xCAFEBABE) == target_xor_result         # obscure XOR relation
    cond2 = (x & 1) == 1                                  # x must be odd
    cond3 = (sum(int(d) for d in str(x)) % 13) == 10      # digit-sum modulo check

    return cond1 and cond2 and cond3
None
7331726659
Proposer: gpt-5-mini-2025-08-07 Solver: gpt-5.2-2025-12-11
1 vs 0
#2 Sample Solution Wrong
import hashlib
import re

def mystery(x):
    """
    Takes a string or number. Returns True for one very particular input form.
    """
    # Canonicalize input to a string (no surrounding whitespace)
    if isinstance(x, (int, float)):
        s = repr(x)
    elif isinstance(x, str):
        s = x.strip()
    else:
        return False

    # Must look like: FLAG{...} with exactly 32 lowercase hex chars inside
    m = re.fullmatch(r"FLAG\{([0-9a-f]{32})\}", s)
    if not m:
        return False

    token = m.group(1).encode("ascii")

    # Check 1: fixed digest prefix
    d = hashlib.sha256(token).hexdigest()
    if not d.startswith("00c0ffee"):
        return False

    # Check 2: a second, different hash constraint
    e = hashlib.blake2b(token, digest_size=16).hexdigest()
    if e[8:16] != "deadbeef":
        return False

    # Check 3: tie it to the token itself in a non-obvious way
    # (prevents trivially pasting in a known preimage unless it matches the internal relation)
    if int(d[-8:], 16) != (int(m.group(1)[:8], 16) ^ 0xA5A5A5A5):
        return False

    return True
"FLAG{e3b0c44298fc1c149afbf4c8996fb924}"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5-mini-2025-08-07
1 vs -1
#3 Solver Failed
def mystery(x):
    """
    mystery accepts either an int or a string (strings are interpreted in a few
    ways). It returns True for exactly one integer value hidden inside a web
    of arithmetic expressions below.
    """
    # Accept a few string forms by converting to int and reusing the int branch.
    if isinstance(x, str):
        s = x.strip()
        # Prefer a base-36 interpretation, but also allow 0x-prefixed hex.
        try:
            return mystery(int(s, 36))
        except Exception:
            pass
        if s.lower().startswith("0x"):
            try:
                return mystery(int(s, 16))
            except Exception:
                pass
        return False

    if not isinstance(x, int):
        return False

    # Build the hidden target with several intertwined computations.
    # These intermediate values are intentionally named and computed in a way
    # that the final value is not obvious at a glance.
    # Component 1: a single large power
    comp_pow = 3 ** 20            # 3**20

    # Component 2: another independent power
    comp_smallpow = pow(5, 10)    # 5**10

    # Component 3: a small constant adjustment (two small primes multiplied)
    comp_adjust = 7 * 11

    # Mix them: add, subtract small correction, scale, then add a hex constant.
    mixed = (comp_pow + comp_smallpow - comp_adjust) * 13
    hidden_constant = mixed + 0xC0FFEE

    return x == hidden_constant
45467810767
45467797767
Proposer: gpt-5-mini-2025-08-07 Solver: gpt-5.2-2025-12-11
2 vs -1
#4 Sample Solution Wrong
import hashlib
import re

def mystery(x):
    """
    Accepts a string or a number.
    Returns True only for a very specific input that is hard to guess by inspection.
    """
    # Canonicalize to a clean string.
    if isinstance(x, bytes):
        try:
            s = x.decode("utf-8", "strict")
        except Exception:
            return False
    elif isinstance(x, (int, float)):
        # repr() is intentionally used (not str()) to make numeric forms fussier.
        s = repr(x)
    elif isinstance(x, str):
        s = x
    else:
        return False

    s = s.strip()

    # Require exact format.
    m = re.fullmatch(r"GLHF\{([0-9a-f]{32})\}", s)
    if not m:
        return False

    token_hex = m.group(1)
    token = bytes.fromhex(token_hex)

    # Several intertwined checks; any mismatch fails.
    d1 = hashlib.sha256(token).digest()
    d2 = hashlib.blake2s(token, digest_size=16).digest()
    d3 = hashlib.md5(token).digest()

    # Check A: SHA-256 has a specific 4-byte prefix.
    if d1[:4] != bytes.fromhex("c0ffee42"):
        return False

    # Check B: BLAKE2s has a specific 4-byte suffix.
    if d2[-4:] != bytes.fromhex("deadbeef"):
        return False

    # Check C: token must satisfy a non-obvious relation to its own digests.
    # (Ties the token bits to the hashes so you can't freely swap in any preimage.)
    if (token[0] ^ token[15]) != (d3[0] ^ d3[15] ^ 0x5A):
        return False

    # Check D: another relation that depends on both digests and token bytes.
    lhs = int.from_bytes(token[4:8], "big") ^ int.from_bytes(d2[0:4], "big")
    rhs = int.from_bytes(d1[-4:], "big") ^ 0x13579BDF
    if lhs != rhs:
        return False

    return True
"GLHF{00000000000000000000000000000000}"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5-mini-2025-08-07
2 vs -2
#5 Solver Failed
import re
import math

def mystery(x):
    """
    Accepts either an int or several string encodings; returns True only for one
    specific integer value constructed by a sequence of intertwined arithmetic
    steps below.

    String handling:
    - If given a string matching the pattern KEY{...}, the inside is interpreted
      as a base-36 integer and reused.
    - Otherwise, plain base-36 or hex ("0x...") strings are also accepted.
    """

    # Normalize string forms into the int branch when possible.
    if isinstance(x, str):
        s = x.strip()
        m = re.fullmatch(r"KEY\{([0-9a-z]+)\}", s, re.IGNORECASE)
        if m:
            try:
                return mystery(int(m.group(1), 36))
            except Exception:
                return False
        # Try direct base-36
        try:
            return mystery(int(s, 36))
        except Exception:
            pass
        # Try hex with 0x prefix
        if s.lower().startswith("0x"):
            try:
                return mystery(int(s, 16))
            except Exception:
                pass
        return False

    # Only integers reach here
    if not isinstance(x, int):
        return False

    # --- Build the hidden target through many steps ---
    # Step A: two modest powers
    comp_a = 3 ** 10          # 59049
    comp_b = 7 ** 7           # 823543

    # Step B: a small composite product
    comp_c = 11 * 13 * 17     # 2431

    # Step C: a short prime-sum that looks arbitrary
    primes_12_sum = sum([2,3,5,7,11,13,17,19,23,29,31,37])  # 197

    # Step D: mix the large-ish parts (multiplicative core)
    core = comp_a * comp_b    # 48,629,390,607

    # Step E: add the small entanglement
    mixed = core + (comp_c * primes_12_sum)  # 48,629,869,514

    # Step F: scale, then adjust by a readable hex constant
    scaled = mixed * 13
    adjusted = scaled + 0xC0FFEE

    # Final small tweak (subtract a tiny constant derived earlier)
    target = adjusted - primes_12_sum

    # All checks are tied to exact equality with the constructed target.
    return x == target
632200950615
632200951915
Proposer: gpt-5-mini-2025-08-07 Solver: gpt-5.2-2025-12-11
3 vs -2
#6 Sample Solution Wrong
import hashlib
import re

def mystery(x):
    """
    Accepts str/bytes/int. Returns True only for one very particular 24-hex token
    wrapped as: LAMBDA{<24 lowercase hex>}
    """
    # Canonicalize to a stripped string
    if isinstance(x, bytes):
        try:
            s = x.decode("utf-8", "strict")
        except Exception:
            return False
    elif isinstance(x, int):
        # allow ints but make them awkward: interpret as hex with no 0x
        if x < 0:
            return False
        s = format(x, "x")
    elif isinstance(x, str):
        s = x
    else:
        return False
    s = s.strip()

    m = re.fullmatch(r"LAMBDA\{([0-9a-f]{24})\}", s)
    if not m:
        return False

    tok_hex = m.group(1)
    tok = bytes.fromhex(tok_hex)  # 12 bytes

    # Hard-to-see constraints (mix of hashes + structural relations)
    d_sha = hashlib.sha256(tok).digest()
    d_b2s = hashlib.blake2s(tok, digest_size=16).digest()
    d_md5 = hashlib.md5(tok).digest()

    # 1) SHA-256 has a fixed 3-byte prefix
    if d_sha[:3] != bytes.fromhex("c0ffee"):
        return False

    # 2) BLAKE2s has a fixed 2-byte suffix
    if d_b2s[-2:] != bytes.fromhex("babe"):
        return False

    # 3) Token nibble-level checksum against SHA tail
    #    (ties token content to its own digest)
    nib_sum = sum(((b >> 4) + (b & 0xF)) for b in tok) & 0xFF
    if nib_sum != d_sha[-1]:
        return False

    # 4) Cross-hash relation involving MD5 and BLAKE2s
    if (d_md5[0] ^ d_md5[-1] ^ tok[0] ^ tok[-1]) != d_b2s[0]:
        return False

    # 5) A lightweight "format-like" constraint hidden as arithmetic
    #    (prevents trivial all-zero / all-FF style candidates)
    if ((tok[2] + tok[5] * 3 + tok[8] * 7) & 0xFF) != (d_md5[7] ^ 0x5A):
        return False

    return True
"LAMBDA{6d2f7c1b9a3e4f8c0a1d2e3f}"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5-mini-2025-08-07
3 vs -3
#7 Solver Failed
import re

def mystery(x):
    """
    Very terse description (visible to solver):
    - Accepts either an int or a few string encodings (decimal, hex with 0x, or CRT{...} as base-36).
    - Returns True only for integers satisfying several intertwined congruences and a checksum.

    The internal constants and constraints are intentionally mixed and non-obvious.
    """
    # String handling: allow a wrapped base-36 form CRT{...}, plain decimal, or 0x-prefixed hex.
    if isinstance(x, str):
        s = x.strip()
        m = re.fullmatch(r"CRT\{([0-9a-z]+)\}", s, re.IGNORECASE)
        if m:
            try:
                return mystery(int(m.group(1), 36))
            except Exception:
                return False
        # decimal
        if re.fullmatch(r"[+-]?\d+", s):
            try:
                return mystery(int(s, 10))
            except Exception:
                return False
        # hex
        if s.lower().startswith("0x"):
            try:
                return mystery(int(s, 16))
            except Exception:
                return False
        return False

    # Only integers reach here
    if not isinstance(x, int):
        return False
    if x < 0:
        return False

    # A web of congruences (co-prime moduli) plus a digit-checksum -- all must hold.
    # These were chosen so that finding a satisfying x by inspection is difficult.
    cond1 = (x % 101) == 17
    cond2 = (x % 103) == 23
    cond3 = (x % 107) == 5

    # A small checksum on the decimal representation to entangle the numeric digits.
    sdig = sum(int(d) for d in str(x))
    cond4 = (sdig % 7) == 1

    return cond1 and cond2 and cond3 and cond4
25467921
821551
Proposer: gpt-5-mini-2025-08-07 Solver: gpt-5.2-2025-12-11
4 vs -3
#8 Sample Solution Wrong
import re
import hashlib
import base64
import binascii

def mystery(x):
    """
    mystery(x) accepts str/bytes/int.
    It returns True only for a very particular hidden payload that passes a chain of
    transformations, checksums, and hash-derived constraints.
    """

    # --- Canonicalize input to bytes "b" in a fussy way ---
    if isinstance(x, bytes):
        s = x.decode("utf-8", "strict")
    elif isinstance(x, int):
        if x < 0:
            return False
        # represent int in base36 (lowercase) without prefixes
        digits = "0123456789abcdefghijklmnopqrstuvwxyz"
        if x == 0:
            s = "0"
        else:
            n = x
            out = []
            while n:
                n, r = divmod(n, 36)
                out.append(digits[r])
            s = "".join(reversed(out))
        s = "ID{" + s + "}"
    elif isinstance(x, str):
        s = x
    else:
        return False

    s = s.strip()

    # Two accepted syntaxes: a wrapped base64-url token, or an ID{base36} integer wrapper.
    m = re.fullmatch(r"TOK\{([A-Za-z0-9\-_]{16,80})\}", s)
    if m:
        tok = m.group(1)
        # urlsafe base64, accept missing padding
        pad = "=" * ((4 - (len(tok) % 4)) % 4)
        try:
            b = base64.urlsafe_b64decode(tok + pad)
        except Exception:
            return False
    else:
        m = re.fullmatch(r"ID\{([0-9a-z]+)\}", s)
        if not m:
            return False
        try:
            n = int(m.group(1), 36)
        except Exception:
            return False
        # Encode n into minimal big-endian bytes (but at least 1 byte)
        blen = max(1, (n.bit_length() + 7) // 8)
        b = n.to_bytes(blen, "big")

    # --- Structure check (length + lightweight "looks random" constraints) ---
    if len(b) != 18:
        return False

    # No obvious repeated-pattern bytes; also forces some entropy
    if len(set(b)) < 12:
        return False

    # --- CRC32 gate (fast, but opaque in combination) ---
    if (binascii.crc32(b) & 0xFFFFFFFF) != 0xA17C3B92:
        return False

    # --- Hash braid: sha256 + blake2s + md5 with cross-relations ---
    d_sha = hashlib.sha256(b).digest()
    d_b2s = hashlib.blake2s(b, digest_size=16).digest()
    d_md5 = hashlib.md5(b).digest()

    # Condition A: SHA256 prefix
    if d_sha[:3] != bytes.fromhex("c0ffee"):
        return False

    # Condition B: BLAKE2s has fixed middle nibble-pattern (hard to spot)
    if (d_b2s[7] ^ d_b2s[9] ^ 0x5A) != 0xC3:
        return False

    # Condition C: MD5 tail vs token bytes (ties content to hash)
    if (d_md5[-1] ^ b[0] ^ b[-1]) != 0x7D:
        return False

    # Condition D: a derived 32-bit relation mixing all three digests
    lhs = int.from_bytes(d_sha[-4:], "big") ^ int.from_bytes(d_b2s[:4], "big")
    rhs = (int.from_bytes(d_md5[4:8], "big") + 0x1234567) & 0xFFFFFFFF
    if lhs != rhs:
        return False

    # Condition E: tiny semantic check hidden as arithmetic on bytes
    # (prevents "I found a hash preimage but it was trivial structure")
    if ((b[2] * 3 + b[5] * 5 + b[8] * 7 + b[11] * 11) & 0xFF) != (d_sha[13] ^ 0xA6):
        return False

    return True
"TOK{c29sdmUtdGhpcy1ub3c}"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5-mini-2025-08-07
4 vs -4
#9 Solved
import re

def mystery(x):
    """
    Accepts either an int or several string encodings (0x-hex or HEX{...}).
    Returns True for exactly one 64-bit integer value, assembled from multiple
    intertwined bit-ops and arithmetic steps below.
    """
    # --- String handling: allow 0x... hex or HEX{...} wrapper ---
    if isinstance(x, str):
        s = x.strip()
        # Accept explicit 0x-prefixed hex
        if s.lower().startswith("0x"):
            try:
                return mystery(int(s, 16))
            except Exception:
                return False
        # Accept a wrapped hex form: HEX{deadbeef...}
        m = re.fullmatch(r"HEX\{([0-9a-fA-F]+)\}", s)
        if m:
            try:
                return mystery(int(m.group(1), 16))
            except Exception:
                return False
        return False

    # Only integers proceed past here
    if not isinstance(x, int):
        return False
    if x < 0:
        return False

    # --- A web of computations that ultimately produce a 64-bit target ---
    # The construction intentionally mixes shifts, masks, sums and small constants.
    # The solver must reverse the mesh to find the single x that matches.

    w0 = 0x1234            # 16-bit chunk 0 (highest-order)
    w1 = 0x5678            # chunk 1
    w2 = 0x9ABC            # chunk 2
    w3 = 0xDEF0            # chunk 3 (lowest-order)

    # Stage 1: place chunks into 64-bit lanes with some noise variables
    lane_high = (w0 << 48)            # top 16 bits into 64-bit position
    lane_midhi = (w1 << 32)           # next 16 bits
    lane_midlo = (w2 << 16)           # next 16 bits
    lane_low = w3                     # bottom 16 bits

    # Stage 2: small mixing arithmetic (reversible here)
    mix1 = lane_high + lane_midhi
    mix2 = lane_midlo ^ 0x0000000000000000  # xor with zero (decoy)
    mix3 = (mix2 + lane_low) - 0x0          # another decoy arithmetic

    # Stage 3: a faux "rotation" built from shifts and masks (keeps value unchanged)
    combined = (mix1 | mix3)
    # apply a mask that preserves 64-bit value explicitly
    masked = combined & ((1 << 64) - 1)

    # Stage 4: tiny checksum-esque tweaks that cancel out
    tweak_a = (0x55AA55AA & 0x55AA55AA)    # identity
    tweak_b = (tweak_a ^ tweak_a)          # zero
    target = (masked + tweak_b)            # final 64-bit target

    # The function returns True only for integers exactly equal to the computed target.
    return x == target
0x123456789ABCDEF0
"0x123456789ABCDEF0"
Proposer: gpt-5-mini-2025-08-07 Solver: gpt-5.2-2025-12-11
4 vs -4
#10 Sample Solution Wrong
import re
import hashlib
import hmac
import binascii
import zlib
import base64

def mystery(x):
    """
    Accepts str/bytes/int. Tries to be annoying about canonicalization.

    True iff the canonical byte payload b (exactly 20 bytes) satisfies:
      - several CRC/Adler checks,
      - intertwined relations between SHA-256, BLAKE2s, and HMAC-SHA256,
      - and a small structural constraint.
    """

    # --- Canonicalize input to bytes b ---
    if isinstance(x, bytes):
        b = x
    elif isinstance(x, int):
        if x < 0:
            return False
        # awkward: interpret int as minimal big-endian bytes, then require it be wrapped later
        blen = max(1, (x.bit_length() + 7) // 8)
        b = x.to_bytes(blen, "big")
    elif isinstance(x, str):
        s = x.strip()

        # Accept: KEY{<urlsafe_b64_no_padding>} OR HEX{<even-length hex>}
        m = re.fullmatch(r"KEY\{([A-Za-z0-9\-_]{8,120})\}", s)
        if m:
            tok = m.group(1)
            pad = "=" * ((4 - (len(tok) % 4)) % 4)
            try:
                b = base64.urlsafe_b64decode(tok + pad)
            except Exception:
                return False
        else:
            m = re.fullmatch(r"HEX\{([0-9a-fA-F]{2,200})\}", s)
            if not m:
                return False
            hx = m.group(1)
            if len(hx) % 2:
                return False
            try:
                b = bytes.fromhex(hx)
            except Exception:
                return False
    else:
        return False

    # --- Size gate ---
    if len(b) != 20:
        return False

    # --- Lightweight structure gate (not too informative, but filters junk) ---
    # Require at least 13 distinct bytes and forbid all-ASCII-printable payloads.
    if len(set(b)) < 13:
        return False
    if all(32 <= c <= 126 for c in b):
        return False

    # --- Checksum gates (fast, opaque together) ---
    if (binascii.crc32(b) & 0xFFFFFFFF) != 0xD7721F0B:
        return False
    if (zlib.adler32(b) & 0xFFFFFFFF) != 0x10C2077D:
        return False

    # --- Hash braid ---
    sha = hashlib.sha256(b).digest()
    b2s = hashlib.blake2s(b, digest_size=16).digest()

    # Fixed-but-small fragments
    if sha[:2] != bytes.fromhex("c0ff"):
        return False
    if b2s[-2:] != bytes.fromhex("ee42"):
        return False

    # Cross-relations tying b to its hashes (prevents swapping in arbitrary preimages)
    # Relation 1: xor of selected payload bytes equals a SHA-derived byte.
    if (b[1] ^ b[3] ^ b[7] ^ b[11] ^ b[19]) != sha[17]:
        return False

    # Relation 2: a 32-bit equation mixing SHA tail and BLAKE head.
    lhs = int.from_bytes(sha[-4:], "big") ^ int.from_bytes(b2s[:4], "big")
    rhs = (int.from_bytes(b[8:12], "big") + 0x31415927) & 0xFFFFFFFF
    if lhs != rhs:
        return False

    # HMAC gate: key is derived from the payload itself (annoying to reason about)
    key = hashlib.sha256(b"salt:" + b[0:10]).digest()[:16]
    tag = hmac.new(key, b, hashlib.sha256).digest()
    if tag[6:10] != bytes.fromhex("deadbeef"):
        return False

    return True
"HEX{3c51b5e2a93f7d10cc0a7f18d2e90b44f1a6c8d3}"
Proposer: gpt-5.2-2025-12-11 Solver: gpt-5-mini-2025-08-07
4 vs -5