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deepseek-v3.2-thinking_vs_grok-4-fast-reasoning.jsonl — 10 puzzles

deepseek-v3.2-thinking
0
vs
grok-4-fast-reasoning
-1
#1 Solved
def mystery(x):
    # Obfuscated puzzle: find an integer x that satisfies several conditions.
    if not isinstance(x, int):
        return False
    # Condition 1: x must be prime.
    if x < 2:
        return False
    for i in range(2, int(x**0.5) + 1):
        if x % i == 0:
            return False
    # Condition 2: x must be a palindrome in decimal.
    s10 = str(x)
    if s10 != s10[::-1]:
        return False
    # Condition 3: x must be a palindrome in hexadecimal.
    s16 = hex(x)[2:]
    if s16 != s16[::-1]:
        return False
    # Condition 4: x must be a palindrome in binary.
    s2 = bin(x)[2:]
    return s2 == s2[::-1]
3
5
Proposer: deepseek-v3.2-thinking Solver: grok-4-fast-reasoning
0 vs 0
#2 Solved
def mystery(x):
    if not isinstance(x, int):
        return False
    if x < 0:
        return False
    root = int(x ** 0.5 + 0.5)
    if root * root != x:
        return False
    s10 = str(x)
    if s10 != s10[::-1]:
        return False
    s16 = hex(x)[2:]
    if s16 != s16[::-1]:
        return False
    s2 = bin(x)[2:]
    if s2 != s2[::-1]:
        return False
    return True
0
9
Proposer: grok-4-fast-reasoning Solver: deepseek-v3.2-thinking
0 vs 0
#3 Solved
def mystery(x):
    # Covert input to integer if it's a string
    if isinstance(x, str):
        try:
            x = int(x)
        except:
            return False
    if not isinstance(x, int) or x < 2:
        return False
    # Primality test
    for d in range(2, int(x ** 0.5) + 1):
        if x % d == 0:
            return False
    # Decimal palindrome
    if str(x) != str(x)[::-1]:
        return False
    # Binary palindrome
    b = bin(x)[2:]
    if b != b[::-1]:
        return False
    # Check if x+1 is a perfect cube by exhaustive search
    y = x + 1
    cube = False
    for i in range(1, int(y ** (1/3)) + 2):
        if i * i * i == y:
            cube = True
            break
    if not cube:
        return False
    # Check if x+2 is a perfect square by exhaustive search
    z = x + 2
    square = False
    for j in range(1, int(z ** 0.5) + 2):
        if j * j == z:
            square = True
            break
    if not square:
        return False
    # Check if (x-1)/2 is prime (safe prime condition)
    p = (x - 1) // 2
    if p < 2:
        return False
    for d in range(2, int(p ** 0.5) + 1):
        if p % d == 0:
            return False
    # Check if the number of 1's in binary representation is prime
    ones = bin(x).count('1')
    if ones < 2:
        return False
    for d in range(2, int(ones ** 0.5) + 1):
        if ones % d == 0:
            return False
    return True
7
7
Proposer: deepseek-v3.2-thinking Solver: grok-4-fast-reasoning
0 vs 0
#4 Solved
def mystery(x):
    if not isinstance(x, int):
        return False
    if x < 0:
        return False
    cube = False
    max_i = int(x ** (1/3) + 1) + 2
    for i in range(0, max_i):
        if i * i * i == x:
            cube = True
            break
    if not cube:
        return False
    s10 = str(x)
    if s10 != s10[::-1]:
        return False
    s16 = hex(x)[2:]
    if s16 != s16[::-1]:
        return False
    s2 = bin(x)[2:]
    if s2 != s2[::-1]:
        return False
    return True
0
1
Proposer: grok-4-fast-reasoning Solver: deepseek-v3.2-thinking
0 vs 0
#5 Solved
def mystery(x):
    # x must be a positive integer
    if not isinstance(x, int) or x <= 0:
        return False

    # Condition 1: primality test
    if x < 2:
        return False
    for i in range(2, int(x**0.5) + 1):
        if x % i == 0:
            return False

    # Condition 2: decimal palindrome
    s10 = str(x)
    if s10 != s10[::-1]:
        return False

    # Condition 3: hexadecimal palindrome
    s16 = hex(x)[2:]
    if s16 != s16[::-1]:
        return False

    # Condition 4: exactly 5 ones in binary (5 is prime)
    b = bin(x)[2:]
    if b.count('1') != 5:
        return False

    # Condition 5: binary length is 17 (17 is prime)
    if len(b) != 17:
        return False

    # Condition 6: congruence modulo 8
    if x % 8 != 1:
        return False

    # Condition 7: product of decimal digits divisible by 144
    prod = 1
    for ch in s10:
        prod *= int(ch)
    if prod % 144 != 0:
        return False

    # Condition 8: contains digit '6'
    if '6' not in s10:
        return False

    # Condition 9: not a binary palindrome
    if b == b[::-1]:
        return False

    return True
98689
98689
Proposer: deepseek-v3.2-thinking Solver: grok-4-fast-reasoning
0 vs 0
#6 Solved
def mystery(x):
    if isinstance(x, str):
        try:
            x = int(x)
        except ValueError:
            return False
    if not isinstance(x, int) or x < 2:
        return False
    # Primality test
    for i in range(2, int(x ** 0.5) + 1):
        if x % i == 0:
            return False
    # Decimal palindrome
    s = str(x)
    if s != s[::-1]:
        return False
    # Binary palindrome
    b = bin(x)[2:]
    if b != b[::-1]:
        return False
    # Sum of digits is prime
    sd = sum(int(d) for d in s)
    if sd < 2:
        return False
    for j in range(2, int(sd ** 0.5) + 1):
        if sd % j == 0:
            return False
    # Product of digits is perfect square
    prod = 1
    for d in s:
        prod *= int(d)
    root = int(prod ** 0.5 + 0.5)
    if root * root != prod:
        return False
    return True
313
313
Proposer: grok-4-fast-reasoning Solver: deepseek-v3.2-thinking
0 vs 0
#7 Solved
def mystery(x):
    if type(x) == str:
        try:
            x = int(x)
        except:
            return False
    if not isinstance(x, int) or x < 2:
        return False
    if x % 2 == 0:
        return x == 2
    d = 3
    while d * d <= x:
        if x % d == 0:
            return False
        d += 2
    s = str(x)
    if s != s[::-1]:
        return False
    b = bin(x)[2:]
    if b != b[::-1]:
        return False
    ds = sum(int(c) for c in s)
    if ds < 2:
        return False
    d = 2
    while d * d <= ds:
        if ds % d == 0:
            return False
        d += 1
    dp = 1
    for c in s:
        dp *= int(c)
    if int(dp ** 0.5) ** 2 != dp:
        return False
    if x % 19 != 9:
        return False
    bw = b.count('1')
    if bw < 2:
        return False
    d = 2
    while d * d <= bw:
        if bw % d == 0:
            return False
        d += 1
    bz = b.count('0')
    if int(bz ** 0.5) ** 2 != bz:
        return False
    if '3' not in hex(x)[2:]:
        return False
    return True
313
313
Proposer: deepseek-v3.2-thinking Solver: grok-4-fast-reasoning
0 vs 0
#8 Sample Solution Wrong
def mystery(x):
    if isinstance(x, str):
        try:
            x = int(x)
        except ValueError:
            return False
    if not isinstance(x, int) or x < 2:
        return False
    # Primality test
    if x <= 1:
        return False
    if x <= 3:
        is_prime = True
    if x % 2 == 0 or x % 3 == 0:
        is_prime = False
    else:
        i = 5
        is_prime = True
        while i * i <= x:
            if x % i == 0 or x % (i + 2) == 0:
                is_prime = False
                break
            i += 6
    if not is_prime:
        return False
    # Decimal palindrome for x
    s = str(x)
    if s != s[::-1]:
        return False
    # Binary palindrome
    b = bin(x)[2:]
    if b != b[::-1]:
        return False
    # Square is decimal palindrome
    sq = x * x
    sq_s = str(sq)
    if sq_s != sq_s[::-1]:
        return False
    # Cube is decimal palindrome
    cu = sq * x
    cu_s = str(cu)
    if cu_s != cu_s[::-1]:
        return False
    return True
101
Proposer: grok-4-fast-reasoning Solver: deepseek-v3.2-thinking
0 vs -1
#9 Solved
def mystery(x):
    if isinstance(x, str):
        try:
            x = int(x)
        except:
            return False
    if not isinstance(x, int) or x < 2:
        return False
    if x % 2 == 0:
        if x == 2:
            pass
        else:
            return False
    d = 3
    while d * d <= x:
        if x % d == 0:
            return False
        d += 2
    s = str(x)
    if s != s[::-1]:
        return False
    b = bin(x)[2:]
    if b != b[::-1]:
        return False
    ds = sum(int(c) for c in s)
    if ds < 2:
        return False
    d2 = 2
    while d2 * d2 <= ds:
        if ds % d2 == 0:
            return False
        d2 += 1
    prod = 1
    for c in s:
        prod *= int(c)
    if int(prod ** 0.5) ** 2 != prod:
        return False
    ones = b.count('1')
    if ones < 2:
        return False
    d2 = 2
    while d2 * d2 <= ones:
        if ones % d2 == 0:
            return False
        d2 += 1
    zeros = b.count('0')
    if int(zeros ** 0.5) ** 2 != zeros:
        return False
    h = hex(x)[2:]
    if '3' not in h:
        return False
    if x % 8 != 1:
        return False
    if x % 13 != 1:
        return False
    if x % 19 != 9:
        return False
    if x % 7 != 5:
        return False
    ssq = sum(int(c)**2 for c in s)
    if ssq < 2:
        return False
    d2 = 2
    while d2 * d2 <= ssq:
        if ssq % d2 == 0:
            return False
        d2 += 1
    blen = len(b)
    if int(blen ** 0.5) ** 2 != blen:
        return False
    return True
313
313
Proposer: deepseek-v3.2-thinking Solver: grok-4-fast-reasoning
0 vs -1
#10 Solved
def mystery(x):
    if isinstance(x, str):
        try:
            x = int(x)
        except ValueError:
            return False
    if not isinstance(x, int) or x < 100:
        return False
    # Primality test for x >= 100
    if x % 2 == 0 or x % 3 == 0:
        return False
    i = 5
    while i * i <= x:
        if x % i == 0 or x % (i + 2) == 0:
            return False
        i += 6
    # Decimal palindrome
    s = str(x)
    if s != s[::-1]:
        return False
    # Binary palindrome
    b = bin(x)[2:]
    if b != b[::-1]:
        return False
    # Sum of digits is prime
    sd = sum(int(d) for d in s)
    if sd <= 1:
        return False
    if sd == 2 or sd == 3:
        pass
    elif sd % 2 == 0 or sd % 3 == 0:
        return False
    j = 5
    while j * j <= sd:
        if sd % j == 0 or sd % (j + 2) == 0:
            return False
        j += 6
    # Product of digits is perfect square
    prod = 1
    for d in s:
        prod *= int(d)
    root = int(prod ** 0.5 + 0.5)
    if root * root != prod:
        return False
    # Hamming weight (number of 1's in binary) is prime
    ones = b.count('1')
    if ones <= 1:
        return False
    if ones == 2 or ones == 3:
        pass
    elif ones % 2 == 0 or ones % 3 == 0:
        return False
    k = 5
    while k * k <= ones:
        if ones % k == 0 or ones % (k + 2) == 0:
            return False
        k += 6
    # Sum of squares of digits is prime
    ssq = sum(int(d)**2 for d in s)
    if ssq <= 1:
        return False
    if ssq == 2 or ssq == 3:
        pass
    elif ssq % 2 == 0 or ssq % 3 == 0:
        return False
    m = 5
    while m * m <= ssq:
        if ssq % m == 0 or ssq % (m + 2) == 0:
            return False
        m += 6
    # Hexadecimal representation contains '1'
    h = hex(x)[2:]
    if '1' not in h:
        return False
    return True
313
313
Proposer: grok-4-fast-reasoning Solver: deepseek-v3.2-thinking
0 vs -1