def mystery(x):
if type(x) is not str:
return False
h = 0
for c in x:
h = ((h << 5) - h + ord(c)) & 0xFFFFFFFF
return h == 3318272062
def mystery(x):
# Accept only strings
if type(x) is not str:
return False
import hashlib
s = x.encode('utf-8')
# Check multiple independent cryptographic digests
if hashlib.md5(s).hexdigest() != "9e107d9d372bb6826bd81d3542a419d6":
return False
if hashlib.sha1(s).hexdigest() != "2fd4e1c67a2d28fced849ee1bb76e7391b93eb12":
return False
if hashlib.sha256(s).hexdigest() != "d7a8fbb307d7809469ca9abcb0082e4f8d5651e46d3cdb762d02d0bf37c9e592":
return False
# Additional non-hash constraints to increase difficulty:
# - sum of codepoints modulo 97 equals a specific value
# - must be a pangram (contain all 26 letters at least once, case-insensitive)
if sum(ord(c) for c in x) % 97 != 80:
return False
if len({c.lower() for c in x if c.isalpha()}) != 26:
return False
return True
def mystery(x):
if type(x) is not str:
return False
# length must be 16
if len(x) != 16:
return False
# must be alphanumeric
if not x.isalnum():
return False
# must contain at least one digit, one uppercase, one lowercase
if not any(c.isdigit() for c in x):
return False
if not any(c.isupper() for c in x):
return False
if not any(c.islower() for c in x):
return False
try:
b = x.encode('ascii')
except UnicodeEncodeError:
return False
arr = list(b)
# Step A: XOR with constant sequence
for i in range(16):
arr[i] ^= (i * 13 + 7) & 0xFF
# Step B: Add constant sequence
for i in range(16):
arr[i] = (arr[i] + (i * 5 + 11)) % 256
# Step C: Multiply by odd constant depending on position
for i in range(16):
if i % 3 == 0:
arr[i] = (arr[i] * 3) % 256
elif i % 3 == 1:
arr[i] = (arr[i] * 5) % 256
else:
arr[i] = (arr[i] * 7) % 256
# Step D: Swap pairs
for i in range(0, 16, 2):
arr[i], arr[i+1] = arr[i+1], arr[i]
# Step E: XOR with left neighbor
for i in range(1, 16):
arr[i] ^= arr[i-1]
# Step F: Permute
perm = [7, 2, 15, 4, 11, 6, 13, 0, 9, 14, 3, 8, 5, 10, 1, 12]
new_arr = [0] * 16
for i in range(16):
new_arr[perm[i]] = arr[i]
arr = new_arr
target = b'\x8e\xcc\x8e~\x10\x91\xd1qmq\xc0\x82,\x85o\xa1'
return bytes(arr) == target
def mystery(x):
# Accept only plain str (no bytes, no numbers)
if type(x) is not str:
return False
try:
b = x.encode('ascii')
except UnicodeEncodeError:
# only pure ASCII allowed
return False
# Quick structural filters to reduce accidental matches
if len(b) != 8:
return False
if any(c.isupper() for c in x):
return False
if any(not (32 <= ord(c) <= 126) for c in x):
return False
# Non-cryptographic check (adds a lightweight constraint)
if sum(b) % 13 != 12:
return False
if len(set(x)) != 7:
return False
# Two independent cryptographic digests (must both match)
import hashlib
if hashlib.md5(b).hexdigest() != "5f4dcc3b5aa765d61d8327deb882cf99":
return False
if hashlib.sha1(b).hexdigest() != "5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8":
return False
# A tiny extra bit-twiddle obfuscation to discourage simple eyeballing:
# compute a 32-bit rolling value
h = 0x9e3779b9
for v in b:
h = ((h << 7) | (h >> (32 - 7))) & 0xFFFFFFFF
h = (h ^ v) + 0x7ed55d16
# require a specific 32-bit result
if h != 0x000001bb:
return False
return True
def mystery(x):
if type(x) is not str:
return False
if len(x) != 8:
return False
# must be printable ASCII
if not all(32 <= ord(c) <= 126 for c in x):
return False
# must contain at least one uppercase, lowercase, digit, and special character
if not any(c.isupper() for c in x):
return False
if not any(c.islower() for c in x):
return False
if not any(c.isdigit() for c in x):
return False
if not any(not c.isalnum() for c in x):
return False
# checksum
if sum(ord(c) for c in x) % 97 != 50:
return False
b = x.encode('ascii')
arr = list(b)
# step 1: XOR with linear function of index
for i in range(8):
arr[i] ^= (i * 3 + 5) & 0xFF
# step 2: non-linear mangling
for i in range(8):
arr[i] = (arr[i] + (arr[i] >> 3) - (arr[i] << 2)) & 0xFF
# step 3: multiply by odd constants
mult = [1, 3, 5, 7, 9, 11, 13, 15]
for i in range(8):
arr[i] = (arr[i] * mult[i]) % 256
# step 4: permute
perm = [3, 0, 5, 2, 7, 4, 1, 6]
new_arr = [0] * 8
for i in range(8):
new_arr[perm[i]] = arr[i]
arr = new_arr
# step 5: diffuse with neighbor
for i in range(1, 8):
arr[i] ^= arr[i - 1]
# step 6: final flip
for i in range(8):
arr[i] ^= 0xFF
target = b'\x21\x60\x73\xeb\xad\x0e\xda\x4e'
return bytes(arr) == target
def mystery(x):
# Accept only plain Python str (no bytes, no numbers)
if type(x) is not str:
return False
# Only pure ASCII allowed
try:
b = x.encode('ascii')
except UnicodeEncodeError:
return False
# Structural filters
if len(b) != 12:
return False
if sum(b) % 97 != 23:
return False
if not any(c.isupper() for c in x):
return False
# A deliberately obfuscated but entirely invertible byte transform:
arr = list(b)
# Step 1: add a per-index constant
add = [5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]
for i in range(12):
arr[i] = (arr[i] + add[i]) & 0xFF
# Step 2: a permutation (position i takes value from original index perm[i])
perm = [11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
new = [0] * 12
for i in range(12):
new[i] = arr[perm[i]]
arr = new
# Step 3: final XOR with a per-index key
key2 = [0xAA, 0x55, 0xFF, 0x00, 0x0F, 0xF0, 0x11, 0x22, 0x33, 0x44, 0x77, 0x88]
for i in range(12):
arr[i] ^= key2[i]
target = b'\xe6\x0fu\x8cqziFH4\x00\xdc'
return bytes(arr) == target
def mystery(x):
if type(x) is not str:
return False
if len(x) != 12:
return False
for c in x:
if ord(c) < 32 or ord(c) > 126:
return False
if not any(c.isdigit() for c in x):
return False
if not any(c.isupper() for c in x):
return False
if not any(c.islower() for c in x):
return False
if not any(not c.isalnum() for c in x):
return False
if sum(1 for c in x if c.isupper()) != sum(1 for c in x if c.islower()):
return False
if sum(1 for c in x if not c.isalnum()) != 3:
return False
if sum(ord(c) for c in x) % 100 != 14:
return False
b = list(x.encode('ascii'))
for i in range(12):
b[i] ^= (i * 17 + 23) & 0xFF
for i in range(12):
b[i] = (b[i] + i * 13) & 0xFF
mult = [1, 3, 5, 7, 1, 3, 5, 7, 1, 3, 5, 7]
for i in range(12):
b[i] = (b[i] * mult[i]) & 0xFF
P = [5, 2, 9, 1, 8, 11, 0, 4, 7, 10, 3, 6]
b = [b[P[i]] for i in range(12)]
for i in range(1, 12):
b[i] ^= b[i-1]
Q = [3, 7, 0, 10, 2, 9, 5, 1, 11, 4, 8, 6]
b = [b[Q[i]] for i in range(12)]
for i in range(12):
b[i] ^= 0xAA
for i in range(12):
b[i] = (b[i] + 0x37) & 0xFF
target = b'\xa3\xee\x25\x6b\x40\x01\xe7\x91\x03\x67\xdf\xfd'
return bytes(b) == target
def mystery(x):
# Accept only Python str
if type(x) is not str:
return False
# Only ASCII printable characters allowed
try:
b = x.encode('ascii')
except UnicodeEncodeError:
return False
if len(b) != 14:
return False
if not all(33 <= c <= 126 for c in b):
return False
# Structural constraints to make accidental matches unlikely
if sum(b) % 101 != 49:
return False
if not any(c.isdigit() for c in x):
return False
if not any(c.islower() for c in x):
return False
if not any(c.isupper() for c in x):
return False
if not any(not c.isalnum() for c in x):
return False
arr = list(b)
# Step 1: XOR with per-index key
key1 = [(i * 31 + 73) & 0xFF for i in range(14)]
for i in range(14):
arr[i] ^= key1[i]
# Step 2: add a per-index constant
for i in range(14):
arr[i] = (arr[i] + (i * 17 + 13)) & 0xFF
# Step 3: rotate each byte left by (i % 8)
def rotl(v, k):
k &= 7
if k == 0:
return v & 0xFF
return ((v << k) | (v >> (8 - k))) & 0xFF
for i in range(14):
arr[i] = rotl(arr[i], i % 8)
# Step 4: multiply by odd per-index constants (mod 256)
mult = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27]
for i in range(14):
arr[i] = (arr[i] * mult[i]) & 0xFF
# Step 5: apply a fixed permutation
perm = [13, 0, 11, 4, 9, 2, 7, 10, 1, 6, 5, 12, 3, 8]
new = [0] * 14
for i in range(14):
new[i] = arr[perm[i]]
arr = new
# Step 6: cumulative additive diffusion
for i in range(1, 14):
arr[i] = (arr[i] + arr[i - 1]) & 0xFF
# Step 7: final XOR with a per-index key and compare to target
key2 = [0x5A, 0xC3, 0x7E, 0x1F, 0x88, 0x33, 0x77, 0x99, 0xAA, 0x55, 0x0F, 0xF0, 0x3C, 0xC3]
final = bytes((arr[i] ^ key2[i]) & 0xFF for i in range(14))
target = b'\xce\x7d\x0ex\x1a\xe5\xce\xd9:\xd8\x8d\x18<\x13'
return final == target
def mystery(x):
# Type check
if type(x) is not str:
return False
# Length must be 12
if len(x) != 12:
return False
# All characters must be printable ASCII (32-126)
if not all(32 <= ord(c) <= 126 for c in x):
return False
# Must contain at least one of each character class
if not any(c.isupper() for c in x):
return False
if not any(c.islower() for c in x):
return False
if not any(c.isdigit() for c in x):
return False
if not any(not c.isalnum() for c in x):
return False
# Sum of code points modulo 97 must be 87
if sum(ord(c) for c in x) % 97 != 87:
return False
# Exactly two non-alphanumeric characters
if sum(1 for c in x if not c.isalnum()) != 2:
return False
# Odd number of lowercase letters
if sum(1 for c in x if c.islower()) % 2 != 1:
return False
# Encode to bytes and convert to list of integers
b = x.encode('ascii')
arr = list(b)
# Step 1: XOR with per‑index key
for i in range(12):
arr[i] ^= (i * 31 + 7) & 0xFF
# Step 2: Add per‑index constant
for i in range(12):
arr[i] = (arr[i] + (i * 19 + 11)) & 0xFF
# Step 3: Multiply by odd constants
mult = [3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25]
for i in range(12):
arr[i] = (arr[i] * mult[i]) & 0xFF
# Step 4: Fixed permutation
perm = [5, 2, 9, 1, 8, 11, 0, 4, 7, 10, 3, 6]
arr = [arr[perm[i]] for i in range(12)]
# Step 5: XOR with right neighbor (circular) using a temporary copy
tmp = arr[:]
for i in range(12):
arr[i] = tmp[i] ^ tmp[(i + 1) % 12]
# Step 6: Rotate each byte left by (i%7 + 1) bits
for i in range(12):
r = (i % 7) + 1
arr[i] = ((arr[i] << r) | (arr[i] >> (8 - r))) & 0xFF
# Step 7: Add another per‑index constant
for i in range(12):
arr[i] = (arr[i] + (i * 13 + 17)) & 0xFF
# Step 8: S‑box: multiply by 29 then XOR with 0x7B
for i in range(12):
arr[i] = (arr[i] * 29) & 0xFF
arr[i] ^= 0x7B
# Step 9: Second permutation
perm2 = [3, 7, 0, 10, 2, 9, 5, 1, 11, 4, 8, 6]
arr = [arr[perm2[i]] for i in range(12)]
# Step 10: XOR with a fixed key
key_final = [0xAA, 0x55, 0xFF, 0x00, 0x11, 0x22, 0x33, 0x44,
0x99, 0x88, 0x77, 0x66]
for i in range(12):
arr[i] ^= key_final[i]
# Step 11: Add 0x37 to each byte
for i in range(12):
arr[i] = (arr[i] + 0x37) & 0xFF
# Compare with the target
target = b'\xB7\xFC\x70\x25\x4A\x12\xC7\xD3\x5E\x16\xFB\x17'
return bytes(arr) == target
def mystery(x):
# Accept only Python str
if type(x) is not str:
return False
# Only pure ASCII allowed
try:
b = x.encode('ascii')
except UnicodeEncodeError:
return False
# Structural filters
if len(b) != 5:
return False
if not x.islower():
return False
if not all(97 <= c <= 122 for c in b): # a-z only
return False
if sum(b) % 97 != 47:
return False
# Multiple independent cryptographic digests must match known values.
import hashlib
if hashlib.md5(b).hexdigest() != "5d41402abc4b2a76b9719d911017c592":
return False
if hashlib.sha1(b).hexdigest() != "aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d":
return False
if hashlib.sha256(b).hexdigest() != "2cf24dba5fb0a30e26e83b2ac5b9e29e1b161e5c1fa7425e73043362938b9824":
return False
# A tiny extra check: a simple rolling xor to add low-level mixing
h = 0x12345678
for v in b:
h = ((h << 5) | (h >> (32 - 5))) & 0xFFFFFFFF
h ^= v
if h != 0x9b9e3f7a:
return False
return True