def mystery(x):
if not isinstance(x, str):
return False
if len(x) != 7:
return False
if not x[0].isalpha() or not x[0].isupper():
return False
if not x[1:4].isdigit():
return False
if not x[4].isalpha() or not x[4].islower():
return False
if not x[5:7].isdigit():
return False
if int(x[1:4]) % 7 != 0:
return False
if int(x[5:7]) % 11 != 0:
return False
if ord(x[0]) + ord(x[4]) != 169:
return False
return True
def mystery(x):
if not isinstance(x, str) or len(x) != 6:
return False
v = [ord(c) for c in x]
# Constraints on the ASCII values of the characters
check1 = v[2] * v[3] == 14884
check2 = v[0] * v[5] == 11312
check3 = v[1] * v[4] == 12636
check4 = sum(v[:3]) == 351
check5 = sum(v) == 682
return all([check1, check2, check3, check4, check5])
def mystery(x):
if not isinstance(x, str):
return False
if len(x) != 5:
return False
# All characters must be alphabetic
if not x.isalpha():
return False
# Convert to numbers (A=1, B=2, etc.)
x_upper = x.upper()
nums = [ord(c) - ord('A') + 1 for c in x_upper]
# Check specific constraints
if nums[0] + nums[4] != 27:
return False
if nums[1] * nums[3] != 140:
return False
if nums[2] % 5 != 0:
return False
if sum(nums) != 69:
return False
return True
def mystery(x):
if not isinstance(x, str) or len(x) != 12:
return False
# Convert string to ASCII values
v = [ord(c) for c in x]
# Constraint 1: Symmetry XOR Check
# The string is "folded": index i is paired with index 11-i
# This enforces specific bitwise relationships between symmetric characters.
xor_targets = [36, 1, 13, 3, 51, 40]
if [v[i] ^ v[11-i] for i in range(6)] != xor_targets:
return False
# Constraint 2: Triplet Sums
# The string is split into 4 blocks of 3 characters.
# The sum of ASCII values in each block is fixed.
if sum(v[0:3]) != 278: return False
if sum(v[3:6]) != 267: return False
if sum(v[6:9]) != 321: return False
if sum(v[9:12]) != 318: return False
# Constraint 3: Weighted Global Checksum
# Each character is multiplied by its 1-based position index.
# This binds all values and positions together to ensure uniqueness.
if sum(val * (i + 1) for i, val in enumerate(v)) != 7949:
return False
return True
def mystery(x):
if not isinstance(x, str) or len(x) != 7:
return False
# Check character types
if not (x[0].isupper() and x[1].isdigit() and x[2].islower() and
x[3].isdigit() and x[4].islower() and x[5].isdigit() and x[6].isupper()):
return False
# ASCII value constraints
vals = [ord(c) for c in x]
# Sum of all ASCII values
if sum(vals) != 536:
return False
# Product of digit values
digits = [int(x[i]) for i in [1, 3, 5]]
if digits[0] * digits[1] * digits[2] != 60:
return False
# Sum of uppercase letters
if vals[0] + vals[6] != 157:
return False
# Sum of lowercase letters
if vals[2] + vals[4] != 223:
return False
return True
def mystery(x):
if not isinstance(x, str) or len(x) != 8:
return False
if not x.islower():
return False
vals = [ord(c) for c in x]
# Constraint 1: ASCII Sum
# The sum of all character values must be exactly 870.
if sum(vals) != 870:
return False
# Constraint 2: Position-weighted Sum
# Sum of (ASCII value * (1-based index)) to enforce order.
if sum(v * (i + 1) for i, v in enumerate(vals)) != 3929:
return False
# Constraint 3: Path Length / "Jaggedness"
# Sum of absolute differences between adjacent characters.
if sum(abs(vals[i] - vals[i+1]) for i in range(len(vals)-1)) != 68:
return False
# Constraint 4: Boundary Product
# The product of the first and last characters.
if vals[0] * vals[-1] != 11220:
return False
# Constraint 5: Anchor Character
# The 4th character is fixed.
if x[3] != 'c':
return False
# Constraint 6: Modulo 5 Signature
# A specific pattern of remainders when divided by 5.
if [v % 5 for v in vals] != [2, 2, 0, 4, 1, 0, 1, 0]:
return False
return True
def mystery(x):
if not isinstance(x, str):
return False
if len(x) != 8:
return False
# All must be lowercase letters
if not x.islower() or not x.isalpha():
return False
vals = [ord(c) - ord('a') for c in x]
# Various constraints
if sum(vals) != 89:
return False
if vals[0] * vals[7] != 130:
return False
if vals[2] + vals[5] != 25:
return False
if vals[1] * vals[6] != 90:
return False
if vals[3] + vals[4] != 20:
return False
if sum(vals[i] * (i+1) for i in range(8)) != 433:
return False
return True
def mystery(x):
# Input must be an 8-character lowercase string
if not isinstance(x, str) or len(x) != 8:
return False
if not x.islower() or not x.isalpha():
return False
# Convert to ASCII values
v = [ord(c) for c in x]
# 1. Pairwise Constraints (Local checks)
# Check 0-1: Product
if v[0] * v[1] != 10088:
return False
# Check 2-3: Sum
if v[2] + v[3] != 214:
return False
# Check 4-5: Bitwise XOR
if v[4] ^ v[5] != 24:
return False
# Check 6-7: Bitwise AND
if v[6] & v[7] != 98:
return False
# 2. Global Constraints (Order and consistency checks)
# Binary Weighted Sum: v[0]*1 + v[1]*2 + v[2]*4 ...
if sum(v[i] << i for i in range(8)) != 28002:
return False
# Alternating Sum: v[0] - v[1] + v[2] - v[3] ...
if sum(v[i] * ((-1)**i) for i in range(8)) != 36:
return False
return True
def mystery(x):
if not isinstance(x, int):
return False
if x < 10000 or x >= 100000:
return False
# Must be divisible by 101
if x % 101 != 0:
return False
digits = [int(d) for d in str(x)]
# Sum of digits constraint
if sum(digits) != 22:
return False
# Product of first and last digit
if digits[0] * digits[4] != 8:
return False
# Sum of specific positions
if digits[1] + digits[3] != 4:
return False
# Must NOT be divisible by 7
if x % 7 == 0:
return False
return True
def mystery(x):
if not isinstance(x, str) or len(x) != 8:
return False
if not x.islower() or not x.isalpha():
return False
v = [ord(c) for c in x]
# 1. Chain constraints (linking adjacent characters)
# These operations bind the characters together in a sequence.
if v[0] + v[1] != 221: return False
if v[1] * v[2] != 12876: return False
if v[2] ^ v[3] != 17: return False
if v[3] | v[4] != 103: return False
if v[4] & v[5] != 98: return False
if v[5] - v[6] != 0: return False
if v[6] + v[7] != 218: return False
# 2. Global Weighted Sum
# Sum of (ASCII value * 1-based index) to ensure the specific permutation.
if sum(val * (i + 1) for i, val in enumerate(v)) != 3873:
return False
# 3. Vowel Count
# A semantic check to confirm the nature of the string.
if sum(1 for c in x if c in 'aeiou') != 4:
return False
return True