def mystery(x):
if not isinstance(x, str):
return False
if len(x) != 5:
return False
if not x[0].isdigit():
return False
letters = x[1:4]
if not all(c.isalpha() and c.islower() for c in letters):
return False
if not (letters[0] <= letters[1] <= letters[2]):
return False
if not x[4].isupper():
return False
if not x[4].lower() > letters[2]:
return False
return True
import hashlib
def mystery(x):
if not (isinstance(x, str) and len(x) == 9 and x.isdigit()):
return False
# x represents a 9-digit sequence
nums = [ord(c) - ord('0') for c in x]
# Must use each digit from 1 to 9 exactly once
if len(set(nums)) != 9 or 0 in nums:
return False
# Let the sequence represent a 3x3 grid:
# nums[0] nums[1] nums[2]
# nums[3] nums[4] nums[5]
# nums[6] nums[7] nums[8]
# Define groups of indices for rows, columns, and diagonals
checks = [
nums[0:3], nums[3:6], nums[6:9], # Horizontal
nums[0::3], nums[1::3], nums[2::3], # Vertical
nums[0::4], nums[2:7:2] # Diagonal
]
# Every group must sum to the same magic constant
if any(sum(group) != 15 for group in checks):
return False
# Finally, verify the hash of the string
h = hashlib.sha256(x.encode()).hexdigest()
return h.startswith('0c04257850')
def mystery(x):
if not isinstance(x, str):
return False
if len(x) != 6:
return False
# First two characters must be digits
if not x[:2].isdigit():
return False
# Last four characters must be lowercase letters
if not (x[2:].isalpha() and x[2:].islower()):
return False
# The two digits must sum to exactly 5
digit_sum = int(x[0]) + int(x[1])
if digit_sum != 5:
return False
# The product of the two digits must be even
product = int(x[0]) * int(x[1])
if product % 2 != 0:
return False
# The four letters must be in ascending order
letters = x[2:]
if letters != ''.join(sorted(letters)):
return False
# All four letters must be distinct
if len(set(letters)) != 4:
return False
# The first letter must be 'b' or 'c'
if not ('b' <= letters[0] < 'd'):
return False
return True
def mystery(x):
if not (isinstance(x, str) and len(x) == 8):
return False
# Check character categories: first 4 must be uppercase, last 4 must be digits
if not (x[:4].isalpha() and x[:4].isupper() and x[4:].isdigit()):
return False
# Extract character values
a = [ord(c) for c in x[:4]]
b = [int(d) for d in x[4:]]
# Algebraic constraints on letters
if a[0] + a[1] != 0x96 or a[0] * a[1] != 0x15E0:
return False
if a[2] + a[3] != 0xA0 or a[0] - a[2] != 5:
return False
# Constraints on the digits
if sum(b) != 0x14 or (b[0]**2 + b[1]**2 - b[2]**2 - b[3]**2 != 160):
return False
# Modular arithmetic and weighted check
if int(x[4:]) % 500 != 0x19B:
return False
return sum((i + 1) * ord(c) for i, c in enumerate(x)) == 0x863
def mystery(x):
if not isinstance(x, str) or len(x) != 6:
return False
# Must be 3 digits followed by 3 lowercase letters
if not (x[:3].isdigit() and x[3:].isalpha() and x[3:].islower()):
return False
digits = [int(d) for d in x[:3]]
letters = x[3:]
# Digits must be in ascending order
if digits != sorted(digits):
return False
# Letters must be in ascending order and distinct
if letters != ''.join(sorted(letters)) or len(set(letters)) != 3:
return False
# Each digit must be between 1 and 4
if not all(1 <= d <= 4 for d in digits):
return False
# Sum of digits equals position of first letter in alphabet
digit_sum = sum(digits)
first_letter_pos = ord(letters[0]) - ord('a')
if digit_sum != first_letter_pos:
return False
# Product of digits equals difference between last and first letter
digit_product = 1
for d in digits:
digit_product *= d
letter_diff = ord(letters[2]) - ord(letters[0])
if digit_product != letter_diff:
return False
return True
def mystery(x):
if not (isinstance(x, str) and len(x) == 10):
return False
# The string must follow a specific structure:
# 4 lowercase letters, 2 digits, and 4 uppercase letters
if not (x[:4].isalpha() and x[:4].islower() and
x[4:6].isdigit() and
x[6:].isalpha() and x[6:].isupper()):
return False
# The first 4 characters must follow a palindrome-like pattern (e.g., "abba")
# where the first and second characters are different.
l_vals = [ord(c) for c in x[:4]]
if l_vals[0] != l_vals[3] or l_vals[1] != l_vals[2] or l_vals[0] == l_vals[1]:
return False
# The two digits, when taken together, must form a prime number.
num = int(x[4:6])
if not (all(num % i != 0 for i in range(2, int(num**0.5) + 1)) and num > 1):
return False
# The sum of the two individual digits must equal the count of unique characters in the entire string.
if int(x[4]) + int(x[5]) != len(set(x)):
return False
# The last 4 characters must be distinct uppercase letters that sum to a specific ASCII total.
u_vals = [ord(c) for c in x[6:]]
if sum(u_vals) != 312 or len(set(u_vals)) != 4:
return False
# Finally, the string must satisfy a weighted ASCII sum check.
return sum((i + 1) * ord(c) for i, c in enumerate(x)) == 4239
def mystery(x):
if not isinstance(x, str) or len(x) != 10:
return False
# First 5 characters: lowercase letters
# Last 5 characters: digits
if not (x[:5].isalpha() and x[:5].islower() and x[5:].isdigit()):
return False
letters = x[:5]
digits = x[5:]
# All letters must be unique
if len(set(letters)) != 5:
return False
# All digits must be unique
if len(set(digits)) != 5:
return False
# Letters must be in ascending order
if letters != ''.join(sorted(letters)):
return False
# The digit string, interpreted as a number, must be divisible by 9
num = int(digits)
if num % 9 != 0:
return False
# Sum of letters (as positions) must equal sum of digits
letter_sum = sum(ord(c) - ord('a') for c in letters)
digit_sum = sum(int(d) for d in digits)
if letter_sum != digit_sum:
return False
# The first letter must be from a-d
if letters[0] not in 'abcd':
return False
# The last digit must be odd
if int(digits[-1]) % 2 == 0:
return False
return True
def mystery(x):
if not (isinstance(x, str) and len(x) == 12):
return False
# Dividing the string into three segments
lowers = x[:4]
digits = x[4:8]
uppers = x[8:]
# Segment 1: Must be four lowercase letters, sorted and unique
if not (lowers.islower() and lowers.isalpha()):
return False
if lowers != "".join(sorted(lowers)) or len(set(lowers)) != 4:
return False
if sum(ord(c) for c in lowers) != 400:
return False
# Segment 2: Must be four unique digits
if not (digits.isdigit() and len(set(digits)) == 4):
return False
val = int(digits)
# The middle segment, as a number, must be divisible by 137
# and the sum of its digits must be exactly 17
if val % 137 != 0 or sum(int(d) for d in digits) != 17:
return False
# Segment 3: Must be four uppercase letters, sorted and unique
if not (uppers.isupper() and uppers.isalpha()):
return False
if uppers != "".join(sorted(uppers)) or len(set(uppers)) != 4:
return False
if sum(ord(c) for c in uppers) != 300:
return False
# Final check: A global weighted ASCII sum across the entire string
return sum((i + 1) * ord(c) for i, c in enumerate(x)) == 5524
def mystery(x):
if not isinstance(x, str) or len(x) != 7:
return False
# Structure: 2 digits, 3 lowercase, 2 uppercase
digits = x[:2]
lowers = x[2:5]
uppers = x[5:]
# Digits must be distinct, non-zero
if not (digits.isdigit() and len(set(digits)) == 2 and '0' not in digits):
return False
# Lowercase must be in ascending order, distinct
if not (lowers.islower() and lowers == ''.join(sorted(lowers)) and len(set(lowers)) == 3):
return False
# Uppercase must be in ascending order, distinct
if not (uppers.isupper() and uppers == ''.join(sorted(uppers)) and len(set(uppers)) == 2):
return False
# Digit product equals number of unique letters
digit_product = int(digits[0]) * int(digits[1])
unique_letters = len(set(lowers + uppers))
if digit_product != unique_letters:
return False
# Sum of lowercase positions equals product of uppercase positions
lower_pos_sum = sum(ord(c) - ord('a') for c in lowers)
upper_pos_prod = (ord(uppers[0]) - ord('A')) * (ord(uppers[1]) - ord('A'))
if lower_pos_sum != upper_pos_prod:
return False
# First digit must be less than second digit
if int(digits[0]) >= int(digits[1]):
return False
return True
def mystery(x):
if not (isinstance(x, str) and len(x) == 15):
return False
# Structural check: must follow the pattern XXXXX-NNN-YYYYY
if x[5] != '-' or x[9] != '-':
return False
p1 = x[:5]
p2 = x[6:9]
p3 = x[10:]
# Part 1 and Part 3: Unique uppercase letters, with no overlap
if not (p1.isalpha() and p1.isupper() and len(set(p1)) == 5):
return False
if not (p3.isalpha() and p3.isupper() and len(set(p3)) == 5):
return False
if not set(p1).isdisjoint(p3):
return False
# Part 2: Three unique digits
if not (p2.isdigit() and len(set(p2)) == 3):
return False
# Bitwise XOR sum constraints for the letter blocks
xor1 = 0
for char in p1:
xor1 ^= ord(char)
xor3 = 0
for char in p3:
xor3 ^= ord(char)
if xor1 != 76 or xor3 != 93:
return False
# Relationship between letter block sums and the numeric middle part
s1 = sum(ord(c) for c in p1)
s3 = sum(ord(c) for c in p3)
if int(p2) != (s1 - s3) * 5 + 100:
return False
# Final global weighted check
return sum((i + 1) * ord(c) for i, c in enumerate(x)) == 8006